Reputation: 1690
I have this IntentService (HttpService
) which fetches raw json data from a webservice:
public class HttpService extends IntentService {
public static final String BROADCAST_ACTION = "com.example.HttpService";
public HttpService() {
super("HttpService");
}
@Override
protected void onHandleIntent(Intent intent) {
//code to get a String with jsonData
//Then I send a broadcast
Intent broadcastHttpResponseIntent = new Intent();
broadcastHttpResponseIntent.setAction(BROADCAST_ACTION);
broadcastHttpResponseIntent.putExtra("jsonData", jsonData);
sendBroadcast(broadcastHttpResponseIntent);
}
}
Now from the IntentService that uses HttpService
I'm trying to get the broadcast:
public class RestaurantModel extends IntentService {
public static final String BROADCAST_ACTION = "com.example.RestaurantModel";
public RestaurantModel() {
super("RestaurantModel");
}
@Override
protected void onHandleIntent(Intent intent) {
Log.v("RestaurantModel", "onHandleIntent");
BroadcastReceiver httpBroadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
Log.v("RestaurantModel", "onReceive");
String jsonResponse = intent.getStringExtra("jsonData");
}
};
Intent getRestaurantsJsonIntent = new Intent(RestaurantModel.this, HttpService.class);
getRestaurantsJsonIntent.putExtra("urlRestaurants", intent.getStringExtra("urlRestaurants"));
startService(getRestaurantsJsonIntent);
registerReceiver(httpBroadcastReceiver, new IntentFilter(HttpService.BROADCAST_ACTION));
}
}
SO I'm getting this error:
RestaurantModel has leaked IntentReceiver com.example.RestaurantModel$1@42374590 that was originally registered here. Are you missing a call to unregisterReceiver()?
So I tried unregistering the Receiver but it seems to need a Context to unregister the receiver.
How to receive values from an IntentService into another IntentService?
Upvotes: 2
Views: 600
Reputation: 1536
Agree with @CommonsWare, in case you want to use BroadcaseReceiver inside of an IntentService, register it in the onCreate method and unregister it in the onDestroy method.
public class RestaurantModel extends IntentService {
public static final String BROADCAST_ACTION = "com.example.RestaurantModel";
private BroadcastReceiver httpBroadcastReceiver;
public RestaurantModel() {
super("RestaurantModel");
}
@Override
public void onCreate() {
super.onCreate();
httpBroadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
Log.v("RestaurantModel", "onReceive");
String jsonResponse = intent.getStringExtra("jsonData");
}
};
LocalBroadcastManager.getInstance(getApplicationContext()).registerReceiver(httpBroadcastReceiver);
}
@Override
public void onDestroy() {
super.onDestroy();
LocalBroadcastManager.getInstance(getApplicationContext()).unregisterReceiver(httpBroadcastReceiver);
}
@Override
protected void onHandleIntent(Intent intent) {
Log.v("RestaurantModel", "onHandleIntent");
Intent getRestaurantsJsonIntent = new Intent(RestaurantModel.this, HttpService.class);
getRestaurantsJsonIntent.putExtra("urlRestaurants", intent.getStringExtra("urlRestaurants"));
startService(getRestaurantsJsonIntent);
}
}
Upvotes: 1
Reputation: 1006964
The best answer is: have only one IntentService
.
The next-best answer is: get rid of the broadcast stuff entirely, and have the first IntentService
call startService()
to kick off the second IntentService
.
Upvotes: 1