How to convert the time portion of a Python datetime object to total number of seconds since start of the day

Question

I have a script that returns a datetime object like so:

rec = record[14]    #index 14 is a straight datetime object
rec2 = rec.time()   #sends time part to rec2

All I want to do now is convert rec2 to seconds of type integer. Any insight on how to do this would be greatly appreciated.

Answer 1

The question "Python Time conversion h:m:s to seconds" (that you've linked) shows a simple efficient one-line solution on how to get an integer number of seconds since midnight that works for both datetime.datetime and datetime.time types:

from datetime import timedelta

secs = timedelta(hours=rec.hour, minutes=rec.minute, seconds=rec.second).seconds

Answer 2

I had "solved" this conundrum earlier by adopting code from a similar question, although I had really hoped there was a more direct way. I took @Nolen Royalty's "cheeky" one liner and wrapped it in the int() function is all. In essence:

rec = record[14]       #stores index 14 of a list to rec which is a full datetime object
rec2 = rec.time()      #stores time portion of that datetime object to rec2
rec3 = rec2.strftime('%H:%M:%S')   #uses strftime to convert to string
s = int(sum(int(i) * 60**index for index, i in enumerate(rec3.split(":")[::-1])))  #converts that string to integer

Convoluted, but it works...still, if anyone has anything better I would be very intrigued.

Answer 3

How about this:

rec2.hour*3600 + rec2.minute*60 + rec2.second

I also found this:

Get seconds since midnight in python