CODEWITHSUNDEEP
phpdatetime
Igor O
Igor O

Reputation: 301

Check if I'm passing only a date without time

Is there a way on PHP I can check if I'm posting only a date without a time?

Ex. 
2015-11-18            ->   TRUE
2015-11-18 00:00:00   ->   FALSE
2015-11-18 23:59:00   ->   FALSE

Thank you!

Upvotes: 0

Views: 96

Answers (3)

Mohit Guleriya
Mohit Guleriya

Reputation: 1

This can be done in a simple way . What I have done is , I split the string into an array . As all the 3 strings (Date sample given by you),differentiates from each other by : symbol. So Split it and use count() method.if its split then count() will return value > 1 .That's it in a simple way..

<?php 

//U can use $a=date("Y-m-d");

$a='2015-11-18'; //Here i am taking an Example 
$b=explode(':' , $a);
if(count($b)>1)
{
   echo "FALSE";
}else
{
echo "TRUE";
}

Hope You were expecting something like this .

Note- I have answered as per your question.For general case it will be different.

Upvotes: 0

Sanjuktha
Sanjuktha

Reputation: 1085

To get the current date you can use-

date("Y-m-d")

It gives only the date.

or if you already have a date -

$date = '10.21.2011';
echo date('Y-m-d', strtotime(str_replace('.', '/', $date)));

to validate you can use preg_match-

$date="10.21.2011";

if (preg_match("/^[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1])$/",$date))
    {
        return true;
    }else{
        return false;
    }

$date = "2014-04-01 12:00:00";

preg_match('/(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2})/',$date);

function.checkdate

Upvotes: 1

Glavić
Glavić

Reputation: 43552

You can use my function (or on PHP.net) to validate date&time for this purpose:

var_dump( validateDate('2015-11-18', 'Y-m-d') );           # true
var_dump( validateDate('2015-11-18 00:00:00', 'Y-m-d') );  # false
var_dump( validateDate('2015-11-18 23:59:00', 'Y-m-d') );  # false

demo

Upvotes: 0

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