CODEWITHSUNDEEP
groovy
JohnRU
JohnRU

Reputation: 65

Groovy string parsing into groups

I'd like to parse a string of the form "xx;yy;zz%;tt" into groups, where ; is the delimiter character, and % is the escape character. So that in this example it becomes a list of 3 elements with [xx,yy, zz;tt].

I know of the split method, but it doesn't take an escape character, and it seems like I need a lot of lines and temporary variables to achieve the wanted result. Is there a short way to do this, with closures ?

Upvotes: 2

Views: 89

Answers (1)

Mark B
Mark B

Reputation: 200562

Using a regex with a negative lookbehind to match all semicolons not preceded by a percent sign:

static void main(String[] args) {
    String test = "xx;yy;zz%;tt"
    def arr = test.split(/(?<!%)\;/)
    println(arr)
}

prints:

[xx, yy, zz%;tt]

You have to use the lookbehind in order to prevent characters that precede the semicolon from being captured by the regex.

Upvotes: 4

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