CODEWITHSUNDEEP
stringswiftrangeswift2
Drux
Drux

Reputation: 12670

Creating Range<String.Index> from constant Ints

What is wrong with this piece of code for constructing a range that should then serve in a call to substringWithRange?

let range = Range<String.Index>(start: 0, end: 3)

The Swift compiler (in Xcode 7.1.1) marks it with this error message:

Cannot invoke initializer for type 'Range<Index>' with an argument list of type '(start: Int, end: Int)'

Upvotes: 3

Views: 4166

Answers (2)

Svitlana
Svitlana

Reputation: 3006

You can use various ways

let startIndex = text.startIndex
let endIndex = text.endIndex

var range1 = startIndex.advancedBy(1) ..< text.endIndex.advancedBy(-4)
var range2 = startIndex.advancedBy(0) ..< startIndex.advancedBy(5)
var range3 = startIndex ..< endIndex

let substring = text.substringWithRange(range)

Upvotes: 1

Tim
Tim

Reputation: 2098

You need to reference the startIndex of a specific string, then advance:

let longString = "Supercalifragilistic"
let startIndex = longString.startIndex
let range = Range(start: startIndex, end: startIndex.advancedBy(3))

Upvotes: 8

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