Unique regex for first name and last name

Question

I have a single input where users should enter name and surname. The problem is i need to use checking regEx. There's a list of a requirements:

1. The name should start from Capital Letter (not space)
2. There can't be space stacks

3. It's obligate to support these Name and Surname (all people are able to write theirs first/name). Example:

   John Smith
   and
   Armirat Bair Hossan 
   

4. And the last symbol shouldn't be space.

Please help,

ATM i have regex like

^\\p{L}\\[p{L} ,.'-]+$

but it denies ALL input, which is not good

Thanks for helping me

UPDATE:

CORRECT INPUT: 
"John Smith"
"Alberto del Muerto"

INCORRECT
"   John Smith   "
" John Smith"

Answer 1

Try this one

^[^- '.](?=(?![A-Z]?[A-Z]))(?=(?![a-z]+[A-Z]))(?=(?!.*[A-Z][A-Z]))(?=(?!.*[- '][- '.]))(?=(?!.*[.][-'.]))[A-Za-z- '.]{1,}$

There is also an interactive Demo of this pattern available at an external website.

Edited: New one supporting most of European languages:

^(?=([A-ZÀ-ÝŐŰẞŒ]|([a-zß-ÿőűœ][ '])))(?=(?![a-zß-ÿőűœ]+[A-ZÀ-ÝŐŰẞŒ]))(?=(?!.*[A-ZÀ-ÝŐŰẞŒ][A-ZÀ-ÝŐŰẞŒ]))(?=(?!.*[- '][- ']))[A-ZÀ-ÝŐŰẞŒß-ÿőűœa-z- ']{2,}([a-zß-ÿőűœ]|(, Jr.))$

Name	Result
yyTyue Tgshh	fail: starts with a small letter
CxCx5C5C	fail: numbers
STEVE SMITH	fail: all capital ...
Stev3 Smith	fail: 3 at the end of the name
STeve Smith	fail: ST
Steve SMith	fail: SM
Steve Sm1th	fail: 1 instead of i
John Smith	fail: extra space)
'John Smith	fail: ' at the beginning
John Smith-	fail: - at the end
d'Are to Beaware	passed 100%
Jo Blow	passed 100%
Hyoung Kyoung Wu	passed 100%
Mike O'Neal	passed 100%
Steve Johnson-Smith	passed 100%
Jozef-Schmozev Hiemdel	passed 100%
O Henry Smith	passed 100%
Mathais d'Arras	passed 100%
Martin Luther King Jr	passed 100%
Downtown-James Brown	passed 100%
Darren McCarty	passed 100%
An Ni	passed 100%
George De FunkMaster	passed 100%
Kurtis B-Ball Basketball	passed 100%
Ahmad el Jeffe	passed 100%
André Désirée Jördis	passed 100%
René Jürg	passed 100%
Esmé Adélaïde	passed 100%
Adorján Ágnes	passed 100%
Bendegúz Bertók	passed 100%
Ávg É Ñu	passed 100%
Ógl Ú Üd	passed 100%
Aarón Abrahán Aída	passed 100%
Íñigo Jerónima	passed 100%

function myFunction() {
    
  const pattern = "^(?=([A-ZÀ-ÝŐŰẞŒ]|([a-zß-ÿőűœ][ '])))(?=(?![a-zß-ÿőűœ]+[A-ZÀ-ÝŐŰẞŒ]))(?=(?!.*[A-ZÀ-ÝŐŰẞŒ][A-ZÀ-ÝŐŰẞŒ]))(?=(?!.*[- '][- ']))[A-ZÀ-ÝŐŰẞŒß-ÿőűœa-z- ']{2,}([a-zß-ÿőűœ]|(, Jr.))$";
    var regex = new RegExp(pattern, 'gm');
    var a = document.getElementById("myText");
  var b = a.value;
  var c = regex.test(b);
  var d = document.getElementById("result") ;
  d.innerHTML = "Result:";
  if(b != ""){
      if(c){
          d.innerHTML += " passed";
      }
      else{
        d.innerHTML += " failed";
        }
  }
  else{
    return
  }
}

input[type=text] {
  width: 99%;
  padding: 4px;
  margin: 8px 0;
  display: inline-block;
  border: 1px solid #ccc;
  box-sizing: border-box;
}
button {
  background-color: #04AA6D;
  color: white;
  padding: 4px;
  border: none;
  cursor: pointer;
  width: 25%;
}

button:hover {
  opacity: 0.8;
}

<h2>Name Validation Regex Pattern </h2>
<div class="container">
      <label for="name"><b>Name</b></label>
        <input type="text" id="myText"  placeholder="Enter Your Name" name="name" value="">
</div>
 <div class="container">

<button onclick="myFunction()">Try it</button>
<p id="result"> Result: </p>
</div>
</div>

Answer 2

You can use

^[\p{Lu}\p{M}][\p{L}\p{M},.'-]+(?: [\p{L}\p{M},.'-]+)*$

or

^\p{Lu}\p{M}*+(?:\p{L}\p{M}*+|[,.'-])++(?: (?:\p{L}\p{M}*+|[,.'-])++)*+$

See the regex demo and demo 2

Java declaration:

if (str.matches("[\\p{Lu}\\p{M}][\\p{L}\\p{M},.'-]+(?: [\\p{L}\\p{M},.'-]+)*")) { ... } 
// or if (str.matches("\\p{Lu}\\p{M}*+(?:\\p{L}\\p{M}*+|[,.'-])++(?: (?:\\p{L}\\p{M}*+|[,.'-])++)*+")) { ... } 

The first regex breakdown:

• ^ - start of string (not necessary with matches() method)
• [\p{Lu}\p{M}] - 1 Unicode letter (incl. precomposed ones as \p{M} matches diacritics and \p{Lu} matches any uppercase Unicode base letter)
• [\p{L}\p{M},.'-]+ - matches 1 or more Unicode letters, a ,, ., ' or - (if 1 letter names are valid, replace + with - at the end here)
• (?: [\p{L}\p{M},.'-]+)* - 0 or more sequences of
  • - a space
  • [\p{L}\p{M},.'-]+ - 1 or more characters that are either Unicode letters or commas, or periods, or apostrophes or -.
• $ - end of string (not necessary with matches() method)

NOTE: Sometimes, names contain curly apostrophes, you can add them to the character classes ([‘’]).

The 2nd regex is less effecient but is more accurate as it will only match diacritics after base letters. See more about matching Unicode letters at regular-expressions.info:

To match a letter including any diacritics, use \p{L}\p{M}*+.

Answer 3

You made a typo: the second \\ should be in front of p. However even then there is a check missing for a trailing space

"^\\p{L}[\\p{L} ,.'-]+$"

For a .matches the following would suffice

"\\p{L}[\\p{L} ,.'-]*[\\p{L}.]"

Names like "del Rey, Hidalgo" do not require an initial capital.

Also I would advise to simply .trim() the input; imagine a user regarding at the input being rejected for a spurious blank.

Answer 4

Try this

^[A-Z][a-z]+(([\s][A-Z])?[a-z]+){1,2}$

but use \\ instead \ for java