CODEWITHSUNDEEP
javaregexescaping
user3575963
user3575963

Reputation:

Regex escape sequence error in Java

p = "<a href=\".*?\"\\stitle=\"(.*?\")>.*?<\/a><span class=\"event-nodetype\">\((.*?\)</span><span class=\"event-timeleft\">\()(.*?\)<\/span><li>)";

This is regex i created for

<a href="/bu/?q=node/775" title="YOK ED?LEN MEDEN?YET: GEÇ OSMANLI VE ERKEN CUMHUR?YET DÖNEMLER?NDE GAYR?MÜSL?M VARLI?I">YOK ED?LEN MEDEN?YET: GEÇ OSMANLI VE ERKEN CUMHUR?YET DÖNEMLER?NDE GAYR?MÜSL?M VARLI?I</a><span class="event-nodetype">(Konferans / Kongre / Sempozyum)</span><span class="event-timeleft">(Devam etmekte)</span><li>

But eclipse gives error of

Invalid escape sequence (valid ones are \b \t \n \f \r \" \' \\ )

I put \ to " and other things but still i cant fix it.

What is the problem?

When i split the line into 4 lines

 p = "<a href=\".*?\"\\stitle=\"(.*?\")>"
        + ".*?<\/a><span class=\"event-nodetype\">\(("
        + ".*?\)</span><span class=\"event-timeleft\">\()("
        + ".*?\)<\/span><li>)";

the error seems on line 2.

Upvotes: 0

Views: 36

Answers (1)

Alan Moore
Alan Moore

Reputation: 75272

\" is correct, an so is \\s (but I would use \\s+). All the other backslashes in your regex need to be escaped: \\/, \\(, \\) (/ doesn't need escaping, but doing so doesn't hurt anything). This is for the string literal, not for the regex; the backslash is an escape character for both.

Upvotes: 1

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