Reputation: 3828
I am trying to duplicate and work with images from Facebook profiles. I can get the images just fine. The majority of them are 'jpgs' however, some of them are 'pngs' and even a few are 'gifs'. There may be others that I don't know about.
My issue. I need to find out what type of image they are before I work with them.
The below code works to get the image and with json I get the url... but the last line of code will not work unless I have the right image type.
$json = file_get_contents("http://graph.facebook.com/$user[id]/picture?width=512&height=512&redirect=false");
$decoded = json_decode($json,true);
$url = $decoded['data']['url'];
/// This line will only work if the image is a jpeg or it throws an error.
$source= imagecreatefromjpeg("$url");
Thank you for your help.
Upvotes: 0
Views: 173
Reputation: 584
Grabbed from Create Image From Url Any File Type
$jpeg_image = imagecreatefromfile( 'photo.jpeg' ); $gif_image = imagecreatefromfile( 'clipart.gif' ); $png_image = imagecreatefromfile( 'transparent_checkerboard.PnG' ); $another_jpeg = imagecreatefromfile( 'picture.JPG' ); // This requires you to remove or rewrite file_exists check: $jpeg_image = imagecreatefromfile( 'http://example.net/photo.jpeg' ); // SEE BELOW HO TO DO IT WHEN http:// ARGS IS NEEDED: $jpeg_image = imagecreatefromfile( 'http://example.net/photo.jpeg?foo=hello&bar=world' ); function imagecreatefromfile( $filename ) { if (!file_exists($filename)) { throw new InvalidArgumentException('File "'.$filename.'" not found.'); } switch ( strtolower( pathinfo( $filename, PATHINFO_EXTENSION ))) { case 'jpeg': case 'jpg': return imagecreatefromjpeg($filename); break; case 'png': return imagecreatefrompng($filename); break; case 'gif': return imagecreatefromgif($filename); break; default: throw new InvalidArgumentException('File "'.$filename.'" is not valid jpg, png or gif image.'); break; } }
Upvotes: 1