CODEWITHSUNDEEP
pythonformat
Loïc G.
Loïc G.

Reputation: 3157

format() int as float

I'm wondering if it have a way to do what I want.

Using format string built-in method, it's possible to print a float as an int :

some_float = 1234.5678
print '%02d' % some_float  # 1234

It's also possible to do that by extending the class string.Formatter:

class MyFormatter(Formatter):
    def format_field(self, value, format_spec):
        if format_spec == 't':  # Truncate and render as int
            return str(int(value))
        return super(MyFormatter, self).format_field(value, format_spec)

MyFormatter().format("{0}{1:t}", "", 1234.567)  # returns "1234"

What I want to do

I want to print an int as a float :

some_int = 12345678
print '{WHAT?}'.format(some_int) # I want 1234.5678
print '{WHAT ELSE?}'.format(some_int) # I want 123456.78

Do you have any idea to how to do this ?

Using format or anything else but keep in mind that I do not know in advance the number of decimal digits

Upvotes: 3

Views: 2225

Answers (1)

Daniel
Daniel

Reputation: 42778

You can divide your number by 10000 or 100:

some_int = 12345678
print '{0:.4f}'.format(some_int / 10000.0)
print '{0:.2f}'.format(some_int / 100.0)

or with a variable amount of decimals:

decimals = 3
print '{0:.{1}f}'.format(some_int / 10.0**decimals, decimals)

Upvotes: 6

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