Reputation: 4110
I'm writing an application in which I need serialization to store some data in files. For serialization I want to use the QDataStream class.
I can't compile my code due to this compiler error:
Error 1 error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'const CListItem' (or there is no acceptable conversion) c:\qt\4.8.6\src\corelib\io\qdatastream.h 265
See the relevant code below. Anyone knows what's going on here?
There is a similar question which didn't help me. When I follow the steps described there, I get this (similar) error:
Error 1 error C2678: binary '<<' : no operator found which takes a left-hand operand of type 'QDataStream' (or there is no acceptable conversion) c:\qt\4.8.6\src\corelib\io\qdatastream.h 265
This is my problem:
What I want to serialize is a class called CMPProject.
CMPProject holds
CListModel* m_pData;
QDateTime m_dateTimeCreated;
This is basically what should be serialized.
CMPProject has operators to stream its contents into a QDataStream.
MPProject.h:
#ifndef _MPPROJECT_
#define _MPPROJECT_
#include <QtCore/QString>
#include <QtCore/QFile>
#include <QtCore/QDateTime>
#include "ListModel.h"
class CMPProject
{
public:
// ...
friend QDataStream& operator <<(QDataStream& stream, const CMPProject& project);
friend QDataStream& operator >>(QDataStream& stream, CMPProject& project);
private:
static const quint32 m_streamHeader = 0x1329453;
QFile* m_pFile;
CListModel* m_pData;
QDateTime m_dateTimeCreated;
};
#endif // _MPPROJECT_
The data stream operators in MPProject.cpp:
QDataStream& operator <<(QDataStream& stream, const CMPProject& project)
{
return stream << project.m_dateTimeCreated << *(project.m_pData);
}
QDataStream& operator >>(QDataStream& stream, CMPProject& project)
{
return stream >> project.m_dateTimeCreated >> *(project.m_pData);
}
m_pData
is of type CListModel
. CListModel
contains the actual data stored as a QList<CListItem>
.
To serialize the CListModel I added the according operators in ListModel.h:
#ifndef _LISTMODEL_
#define _LISTMODEL_
#include <QtCore/QAbstractListModel>
#include <QtCore/QList>
#include <QtCore/QStringList>
#include "ListItem.h"
typedef QMap<unsigned int, QString> TValueMap;
class CListModel : public QAbstractListModel
{
public:
// ...
template<typename T>
friend void operator <<(QVariant& data, const QList<T>& target);
template<typename T>
friend void operator >>(const QVariant& data, QList<T>& target);
friend QDataStream& operator <<(QDataStream& stream, const CListModel& listModel);
friend QDataStream& operator >>(QDataStream& stream, CListModel& listModel);
private:
QList<CListItem> m_items;
};
#endif // !_LISTMODEL_
and ListModel.cpp:
template<typename T>
void operator <<(QVariant& data, const QList<T>& target)
{
QVariantList list;
list.reserve(target.count());
for (int i = 0; i < target.count(); i++) {
QVariant item;
item << target[i];
list.append(item);
}
data = list;
}
template<typename T>
void operator >>(const QVariant& data, QList<T>& target)
{
QVariantList list = data.toList();
target.reserve(list.count());
for (int i = 0; i < list.count(); i++) {
T item;
list[i] >> item;
target.append(item);
}
}
QDataStream& operator <<(QDataStream& stream, const CListModel& listModel)
{
// ERROR C2679 does not occur when I change this line to "return stream;"
return stream << listModel.m_items;
}
QDataStream& operator >>(QDataStream& stream, CListModel& listModel)
{
return stream >> listModel.m_items;
}
In order to serialize the contents of listModel.m_items
(objects of type CListItem
) I implemented the according operators in ListItem.h:
#ifndef _LISTITEM_
#define _LISTITEM_
#include <QtCore/QString>
#include <QtCore/QStringList>
#include <QtCore/QDateTime>
#include <QtCore/QVariantMap>
class CListItem
{
public:
// ...
friend void operator <<(QVariant& data, const CListItem& target);
friend void operator >>(const QVariant& data, CListItem& target);
private:
QString m_name;
QString m_domain;
QString m_login;
QString m_password;
QDateTime m_LastModified;
};
#endif // !_LISTITEM_
and ListItem.cpp:
template<typename T>
void operator <<(QVariant& data, const T& target)
{
data = QVariant::fromValue<T>(target);
}
template<typename T>
void operator >>(const QVariant& data, T& target)
{
target = data.value<T>();
}
void operator <<(QVariant& data, const CListItem& target)
{
QVariantMap map;
map["name"] << target.m_name;
map["domain"] << target.m_domain;
map["login"] << target.m_login;
map["password"] << target.m_password;
map["dateModified"] << target.m_LastModified;
data << map;
}
void operator >>(const QVariant& data, CListItem& target)
{
QVariantMap map;
data >> map;
map["name"] >> target.m_name;
map["domain"] >> target.m_domain;
map["login"] >> target.m_login;
map["password"] >> target.m_password;
map["dateModified"] >> target.m_LastModified;
}
Upvotes: 1
Views: 1765
Reputation: 4110
I fixed it.
The problem was that I didn't have operators to put my QList into a QDataStream. But I defined wrappers to store my list in QVariant, so (of course) I just should have used those.
QDataStream& operator <<(QDataStream& stream, const CListModel& listModel)
{
QVariant var;
var << listModel.m_items;
return stream << var;
}
QDataStream& operator >>(QDataStream& stream, CListModel& listModel)
{
QVariant var;
stream >> var;
var >> listModel.m_items;
return stream;
}
Upvotes: 2
Reputation: 19617
It looks like here is no operator<<
overloaded for arguments: QDataStream &
and QList<CListItem> const&
. In the reference here and here, there aren't any documented.
The second error addresses this, but there also should be QList<CListItem>
argument mentioned. Was that the full error message?
Basically, you should be using this:
QDataStream& operator <<(QDataStream& stream, const CListModel& listModel)
{
for(auto const& item : listModel.m_items)
stream << item; // write elements one by one
return stream;
}
This template might serve you for multiple types (or something akin to Pretty-print C++ STL containers):
template <typename Stream, typename Containter>
Stream& operator <<(Stream& stream, const Containter& container)
{
for(auto const& item : container)
stream << item;
return stream;
}
Your code would be valid without making change to operator<<
you defined. Hope that helps.
Upvotes: 1