CODEWITHSUNDEEP
javadouble
Ghilliedrone
Ghilliedrone

Reputation: 85

DecimalFormat not rounding to two decimal places correctly

In the program I am writing I have a percent change function. With the numbers I'm using, it is supposed to return .03, yet I just get 0. Using a calculator, the value not formatted would be 0.03303. I want the number to be truncated after the second decimal place, no rounding at all.

df = new DecimalFormat("###.##;-###.##");
df.setRoundingMode(RoundingMode.DOWN);

//later in code
return df.format(((price-base_price)/price)*100.00D);

Edit: all variable types are doubles. Base price is 756.60 and price is 756.85

Upvotes: 1

Views: 417

Answers (1)

Elliott Frisch
Elliott Frisch

Reputation: 201527

Your assumption about the value calculated in ((price-base_price)/price)*100.00D is incorrect (I think you've probably invoked integer math, try ((price-base_price)/(double)price)*100.00D). When I directly execute,

double value = 0.03303;
DecimalFormat df = new DecimalFormat("###.##;-###.##");
df.setRoundingMode(RoundingMode.DOWN);
System.out.println(df.format(value));

I get the (requested) output

0.03

Upvotes: 4

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