CODEWITHSUNDEEP
xmlxsltxhtml
BernatL
BernatL

Reputation: 72

XSLT select all text and specific node

I would like to select all text from an XHTML file except all hyperlink elements which are needed to be printed fully:

XHTML

<?xml version="1.0" encoding="UTF-8" ?>
<html>
   <body>
      <p>This is a paragraph.</p>
      <p>This is another paragraph.</p>
      <a href="www.link.com">This is a link.</a>
   </body>
</html>

Desired output:

This is a paragraph. This is another paragraph. <a href="www.link.com">This is a link.</a>

I am using the following XSLT, but getting no results:

XSLT

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

   <xsl:output method="text"/>

   <xsl:template match="@*|node()">
      <xsl:apply-templates select="@*|node()"/>
   </xsl:template>

   <xsl:template match="ancestor-or-self::text()">
      <xsl:value-of select="text()"/>
   </xsl:template>

   <xsl:template match="a">
      <xsl:copy>
         <xsl:apply-templates select="@*|node()"/>
      </xsl:copy>
   </xsl:template>

</xsl:stylesheet>

Any help on this will be very appreciated.

Upvotes: 0

Views: 2057

Answers (1)

michael.hor257k
michael.hor257k

Reputation: 116982

Try it this way:

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="a">
    <xsl:copy-of select="."/>
</xsl:template>

</xsl:stylesheet>

Note the output method. See also: http://www.w3.org/TR/xslt/#built-in-rule

Upvotes: 1

Related Questions