Reputation: 401
I have a item table from which i want to get Sum of item quantity
Query:
Select item_id, Sum(qty) from item_tbl group by item_id
Result:
==================
| ID | Quantity |
===================
| 1 | 10 |
| 2 | 20 |
| 3 | 5 |
| 4 | 20 |
The second table is invoice table from which i am getting the item quantity which is sold. I am joining these two tables as
Query:
Select item_tbl.item_id, Sum(item_tbl.qty) as [item_qty],
-isnull(Sum(invoice.qty),0) as [invoice_qty]
from item_tbl
left join invoice on item_tbl.item_id = invoice invoice.item_id group by item_tbl.item_id
Result:
=================================
| ID | item_qty | invoice_qty |
=================================
| 1 | 10 | -5 |
| 2 | 20 | -20 |
| 3 | 10 | -25 | <------ item_qty raised from 5 to 10 ??
| 4 | 20 | -20 |
I don't know if i am joining these tables in right way. Because i want to get everything from item table and available things from invoice table to maintain the inventory. So i use left join. Help please..
Modification
when i added group by item_id, qty i got this:
=================================
| ID | item_qty | invoice_qty |
=================================
| 1 | 10 | -5 |
| 2 | 20 | -20 |
| 3 | 5 | -5 |
| 3 | 5 | -20 |
| 4 | 20 | -20 |
As its a view so ID is repeated. what should i do to avoid this ??
Upvotes: 0
Views: 499
Reputation: 2766
Clearing things up, my answer from the comments explained:
While using left join operation (A left join B) - a record will be created for every matching B record to an A record, also - a record will be created for any A record that has no matching B record, using null values wherever needed to complement the fields from B.
I would advise reading up on Using Joins in SQL when approaching such problems.
Below are 2 possible solutions, using different assumptions.
Without any assumptions regarding primary key:
We have to sum up the item quantity column to determine the total quantity, resulting in two sums that need to be performed, I would advise using a sub query for readability and simplicity.
select item_tbl.item_id, Sum(item_tbl.qty) as [item_qty], -isnull(Sum(invoice_grouped.qty),0) as [invoice_qty]
from item_tbl left join
(select invoice.item_id as item_id, Sum(invoice.qty) as qty from invoice group by item_id) invoice_grouped
on (invoice_grouped.item_id = item_tbl.item_id)
group by item_tbl.item_id
Assuming item_id is primary key for item_tbl:
Now we know we can rely on the fact that there is only one quantity for each item_id, so we can do without the sub query by selecting any (max) of the item quantities in the join result, resulting in a quicker execution plan.
select item_tbl.item_id, Max(item_tbl.qty) as [item_qty], -isnull(Sum(invoice.qty),0) as [invoice_qty]
from item_tbl left join invoice on (invoice.item_id = item_tbl.item_id)
group by item_tbl.item_id
Upvotes: 1
Reputation: 218
If your database design is following the common rules, item_tbl.item_id
must be unique.
So just change your query:
Select item_tbl.item_id, item_tbl.qty as [item_qty],
-isnull(Sum(invoice.qty),0) as [invoice_qty]
from item_tbl
left join invoice on item_tbl.item_id = invoice invoice.item_id group by item_tbl.item_id, item_tbl.qty
Upvotes: 1