CODEWITHSUNDEEP
pythoncurlpython-requestsusergridapigee-baas
Lionel
Lionel

Reputation: 596

unable to post file+data using python-requests

I'm able to post file using curl 

curl -X POST -i -F name='barca' -F country='spain' -F 
file=@/home/messi/Desktop/barca.png 'http://localhost:8080/new_org/hel/concerts'

Which I can get (file) as

 curl -X GET -H 'Accept: image/png' 'http://localhost:8080/new_org/hel/concerts/<id or name of entity>'

But when I tried same thing using requests.post, I got error. Does anybody know why this happen. (Post Error encounter when file pointer is not at last, but when file pointer is at last, I got response 200 but file is not posted)

import requests
url = 'http://localhost:8080/new_org/hel/concerts'
file = dict(file=open('/home/messi/Desktop/barca.png', 'rb'))
data = dict(name='barca', country='spain')
response = requests.post(url, files=file, data=data)

Error: (from usergrid) with response code: 400

{u'duration': 0,
 u'error': u'illegal_argument',
 u'error_description': u'value is null',
 u'exception': u'java.lang.IllegalArgumentException',
 u'timestamp': 1448330119021}

https://github.com/apache/usergrid

Upvotes: 4

Views: 6056

Answers (2)

snoopdave
snoopdave

Reputation: 306

I believe the problem is that Python is not sending a content-type field for the image that you are sending. I traced through the Usergrid code using a debugger and saw that curl is sending the the content-type for the image and Python is not.

I was able to get this exact code to work on my local Usergrid:

import requests
url = 'http://10.1.1.161:8080/test-organization/test-app/photos/'
files = { 'file': ('13.jpg', open('/Users/dave/Downloads/13.jpg', 'rb'), 'image/jpeg')}
data = dict(name='barca', country='spain')
response = requests.post(url, files=files, data=data)

It is possible that Waken Meng's answer did not work because of the syntax of the files variable, but I'm no Python expert.

Upvotes: 9

waken meng
waken meng

Reputation: 21

I met a problem before when i try to upload image files. Then I read the doc and do this part:

You can set the filename, content_type and headers explicitly:

Here is how I define the file_data:

file_data = [('pic', ('test.png', open('test.png'), 'image/png'))]
r = requests.post(url, files=file_data)

file_data should be a a list: [(param_name, (file_name, file, content_type))]

This works for me, hope can help you.

Upvotes: 1

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