CODEWITHSUNDEEP
javauuid
user26270
user26270

Reputation: 7084

Why does UUID.fromString() not throw IllegalArgumentException for this UUID?

I'm trying to validate that a string is a UUID. Apparently I don't understand what a valid UUID is. This is what I thought was an invalid UUID - 55bb6be3-078c-4a49-a4e6-1e05776ed7e81234

But when I pass that to UUID.fromString(), instead of throwing IllegalArgumentException, it returns a uuid with the value 55bb6be3-078c-4a49-bee7-776ed7e81234

Upvotes: 1

Views: 4516

Answers (1)

mtyurt
mtyurt

Reputation: 3449

To throw an IllegalArgumentException, there should be less than 4 dashes - or 5 components. Here is the code part that throws the exception:

 String[] components = name.split("-");
 if (components.length != 5)
     throw new IllegalArgumentException("Invalid UUID string: "+name);

Your input is not invalid, it has overflew components, therefore the returning UUID is different from the input.

Upvotes: 1

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