CODEWITHSUNDEEP
bashposixglob
mate_eu
mate_eu

Reputation: 71

Negating POSIX class bash globbing

I am curious if I could negate POSIX class while performing pattern matching. I have following:

file  file1  file10  file2  file3  file4  file5  file6  file7  file8  file9

Say, I want to ls -l only file : all the files with no digit in the end. I tried following :

ls -l *[^[[:digit:]]]
ls -l *[!digits]
ls -l *[[!:digit:]]

None of above works. That actually work, to some extend (I get file10):

ls *[^1-9]

But that's not a point. And for the record I know that the easiest would be:

ls -l | egrep -v ".*[[:digit:]]$"

Is there any way to negate POSIX class?

Upvotes: 1

Views: 138

Answers (2)

anubhava
anubhava

Reputation: 785266

You can use *[![:digit:]] to match files not ending with digits:

printf "%s\n" *[![:digit:]]
file

Upvotes: 4

choroba
choroba

Reputation: 241918

The outer square brackets denote the character class. The inner ones denote the POSIX class. Negate the character class:

ls -l *[![:digit:]]

Upvotes: 4

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