Reputation: 17804
I'm trying to show Polylines in Leaflet but it doesn't seem to work. Am I missing anything or...? p.s. Coordinate pairs do not contain the same values, so it should yield lines...
//this adds markers to the map, which works
var d = {};
d.coordinates = [[lat,lng],[lat,lng]]
var latLngs = d.coordinates.map(function (c) {
var marker = L.marker(c).addTo(map);
return {
lat: c[0],
lng: c[1]
};
});
//This 'should' add polylines but doesn't ...
var polyline = L.polyline(d.coordinates, { color: 'red', weight: 12 }).addTo(map);
I tried all sorts of variations on the code above, varying with instantiation/factory method like: new L.polyline()
vs L.polyline()
and trying upper- and lowercase Polyline. I tried passing arrays of [double, double]
and [L.LatLng, L.LatLng]
and even [{lat:lat,lng:lng}]
but nothing seems to work... I really must be overlooking a simple thing...
I'm using Leaflet 0.7.
Edit:
As shown in the jsFiddle by ghybs it should work. I updated my code to the following:
var firstpolyline = L.polyline(d.coordinates, {
color: 'red',
weight: 12
}).addTo(map);
I also added identical logging statements in both the jsFiddle and my solution.
console.log(firstpolyline); //polyline for jsFiddle
console.log(map);
console.log(d.coordinates);
Those yield this (left is custom solution which is not showing a line, right is jsFiddle which is showing a line). Manually copy-pasting different coordinates pairs of my solution to the jsFiddle just works...:
I'm really lost here :(
Upvotes: 1
Views: 3727
Reputation: 53290
There is no reason to add an extra .polyline
after the factory L.polyline()
.
var polyline2 = L.polyline(d.coordinates, {color: 'red', weight: 12}).addTo(map);
Demo: http://jsfiddle.net/ve2huzxw/48/
Side note: you should use a single equal sign (=
) for assignment in d.coordinates == [[lat,lng],[lat,lng]]
Upvotes: 0