CODEWITHSUNDEEP
javascriptphpregex
user3733831
user3733831

Reputation: 2926

Regular expression for unique number.

I need a regular expression that validate an unique value. It has a unique 9 digit number, in the format 000000000A (where 0 is a digit and A is a letter). Only allows letter "V" or "X" for last string.

I can do it for digits but not sure how to modify for last string. 

^[1-9][0-9]{9}$

Hope somebody may help me out.

Upvotes: 4

Views: 2083

Answers (4)

Anders
Anders

Reputation: 2316

You could do:

^[1-9][0-9]{8}[VX]$

Or more generically if the suffix were more than one character you could use groups. As it appears you are using POSIX Extended Regular Expression (ERE) syntax, you can also use parenthesis for groups, like:

^[1-9][0-9]{8}(V|X)$

Link to ERE syntax

Link to JavaScript Regex standard

Upvotes: 0

Tushar
Tushar

Reputation: 87203

You can use character class [VX], it'll match a single character from it.

^[1-9][0-9]{8}[VX]$

Or, OR condition as follow

^[1-9][0-9]{8}(V|X)$

Update:

To match the alphabets case-insensitively, use i flag or the lowercase characters can also be added in class

^[1-9][0-9]{8}[VvXx]$

Upvotes: 2

davidkonrad
davidkonrad

Reputation: 85538

Why not just d{9} ? /\d{9}(V|X)/ seems easier. 

var test = "qwerty000000000Xqwerty";

console.log(test.match(/\d{9}(V|X)/));

http://jsfiddle.net/u5gmfjeL/1/ - matches 830363670V as well.

case insensitive add /i -> /\d{9}(V|X)/i -> http://jsfiddle.net/u5gmfjeL/2/

Upvotes: 1

Machavity
Machavity

Reputation: 31654

You can also try something simpler (unless the leading number cannot be 0)

\d{9}[VX]

Upvotes: 1

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