Reputation: 433
I have a code that works just fine to check if element is outside of bottom viewport, as follows:
function posY(elm) {
let test = elm, top = 0;
while(!!test && test.tagName.toLowerCase() !== "body") {
top += test.offsetTop;
test = test.offsetParent;
}
return top;
}
function viewPortHeight() {
let de = document.documentElement;
if(!window.innerWidth)
{ return window.innerHeight; }
else if( de && !isNaN(de.clientHeight) )
{ return de.clientHeight; }
return 0;
}
function scrollY() {
if( window.pageYOffset ) { return window.pageYOffset; }
return Math.max(document.documentElement.scrollTop, document.body.scrollTop);
}
function checkvisible (elm) {
let vpH = viewPortHeight(), // Viewport Height
st = scrollY(), // Scroll Top
y = posY(elm);
return (y > (vpH + st));
}
if (hasActivity && isHidden) {
isVisibleCSS = <div className='onscreen'>More activity below ↓</div>;
} else if (hasActivity && !isHidden) {
//technically, there's no need for this here, but since I'm paranoid, let's leave it here please.
}
My question is, how can I adapt this code or create a new one similar to this one that identifies when element is outside of top viewport?
Cheers.
Upvotes: 1
Views: 1685
Reputation: 9654
For an element to be completely off the view top then the sum of the element's top offset and it's height, like in this JS Fiddle
var $test = document.getElementById('test'),
$tOffset = $test.offsetTop,
$tHeight = $test.clientHeight,
$winH = window.innerHeight,
$scrollY;
window.addEventListener('scroll', function() {
$scrollY = window.scrollY;
if ($scrollY > ($tOffset + $tHeight)) {
console.log('out of the top');
}
});
body {
margin: 0;
padding: 0;
padding-top: 200px;
height: 1500px;
}
#test {
width: 100px;
height: 150px;
background-color: orange;
margin: 0 auto;
}
<div id="test"></div>
Upvotes: 2