Brent
Brent

Reputation: 16869

How can I remove the first line of a text file using bash/sed script?

I need to repeatedly remove the first line from a huge text file using a bash script.

Right now I am using sed -i -e "1d" $FILE - but it takes around a minute to do the deletion.

Is there a more efficient way to accomplish this?

Upvotes: 802

Views: 822358

Answers (21)

Ed Morton
Ed Morton

Reputation: 204381

For truly in-place deletion of lines at the head of a file:

$ cat file
1
2
3
4
5

$ bytes=$(head -1 file |wc -c)

$ dd if=file bs="$bytes" skip=1 conv=notrunc of=file
4+0 records in
4+0 records out
8 bytes copied, 0.0002447 s, 32.7 kB/s

$ truncate -s "-$bytes" file

$ cat file
2
3
4
5

It will be orders of magnitude slower than using sed -i '1d' or similar that use a temp file though so only use it if you don't have enough disk space to make a copy of the input file.

Upvotes: 1

amit
amit

Reputation: 5559

With sed, the pattern '1d' will delete the first line. Additionally, the -i flag can be used to update the file "in place". 1

sed -i '1d' filename

1 sed -i automatically creates a temporary file with the desired changes, and then replaces the original file.

Upvotes: 366

Freeman
Freeman

Reputation: 12748

Also check these ways :

mapfile -t lines < 1.txt && printf "%s\n" "${lines[@]:1}" > new.txt

#OR

awk 'NR>1' old.txt > new.txt

#OR

cut -d $'\n' -f 2- old.txt > new.txt

Upvotes: 0

aidanmelen
aidanmelen

Reputation: 6604

You can use the sed command to delete arbitrary lines by line number

# create multi line txt file
echo """1. first
2. second
3. third""" > file.txt

deleting lines and printing to stdout

$ sed '1d' file.txt 
2. second
3. third

$ sed '2d' file.txt 
1. first
3. third

$ sed '3d' file.txt 
1. first
2. second

# delete multi lines
$ sed '1,2d' file.txt 
3. third

# delete the last line
sed '$d' file.txt 
1. first
2. second

use the -i option to edit the file in-place

$ cat file.txt 
1. first
2. second
3. third

$ sed -i '1d' file.txt

$cat file.txt 
2. second
3. third

Upvotes: 1

zabop
zabop

Reputation: 7922

tail +2 path/to/your/file

works for me, no need to specify the -n flag. For reasons, see Aaron's answer.

Upvotes: 2

Murilo Perrone
Murilo Perrone

Reputation: 504

Based on 3 other answers, I came up with this syntax that works perfectly in my Mac OSx bash shell:

line=$(head -n1 list.txt && echo "$(tail -n +2 list.txt)" > list.txt)

Test case:

~> printf "Line #%2d\n" {1..3} > list.txt
~> cat list.txt
Line # 1
Line # 2
Line # 3
~> line=$(head -n1 list.txt && echo "$(tail -n +2 list.txt)" > list.txt)
~> echo $line
Line # 1
~> cat list.txt
Line # 2
Line # 3

Upvotes: 0

Mark Reed
Mark Reed

Reputation: 95335

If you want to modify the file in place, you could always use the original ed instead of its streaming successor sed:

ed "$FILE" <<<$'1d\nwq\n'

The ed command was the original UNIX text editor, before there were even full-screen terminals, much less graphical workstations. The ex editor, best known as what you're using when typing at the colon prompt in vi, is an extended version of ed, so many of the same commands work. While ed is meant to be used interactively, it can also be used in batch mode by sending a string of commands to it, which is what this solution does.

The sequence <<<$'1d\nwq\n' takes advantage of modern shells' support for here-strings (<<<) and ANSI quotes ($'...') to feed input to the ed command consisting of two lines: 1d, which deletes line 1, and then wq, which writes the file back out to disk and then quits the editing session.

Upvotes: 13

egors
egors

Reputation: 156

This one liner will do:

echo "$(tail -n +2 "$FILE")" > "$FILE"

It works, since tail is executed prior to echo and then the file is unlocked, hence no need for a temp file.

Upvotes: 5

agc
agc

Reputation: 8446

The sponge util avoids the need for juggling a temp file:

tail -n +2 "$FILE" | sponge "$FILE"

Upvotes: 19

Aaron Digulla
Aaron Digulla

Reputation: 328760

Try tail:

tail -n +2 "$FILE"

-n x: Just print the last x lines. tail -n 5 would give you the last 5 lines of the input. The + sign kind of inverts the argument and make tail print anything but the first x-1 lines. tail -n +1 would print the whole file, tail -n +2 everything but the first line, etc.

GNU tail is much faster than sed. tail is also available on BSD and the -n +2 flag is consistent across both tools. Check the FreeBSD or OS X man pages for more.

The BSD version can be much slower than sed, though. I wonder how they managed that; tail should just read a file line by line while sed does pretty complex operations involving interpreting a script, applying regular expressions and the like.

Note: You may be tempted to use

# THIS WILL GIVE YOU AN EMPTY FILE!
tail -n +2 "$FILE" > "$FILE"

but this will give you an empty file. The reason is that the redirection (>) happens before tail is invoked by the shell:

  1. Shell truncates file $FILE
  2. Shell creates a new process for tail
  3. Shell redirects stdout of the tail process to $FILE
  4. tail reads from the now empty $FILE

If you want to remove the first line inside the file, you should use:

tail -n +2 "$FILE" > "$FILE.tmp" && mv "$FILE.tmp" "$FILE"

The && will make sure that the file doesn't get overwritten when there is a problem.

Upvotes: 1414

Ingo Baab
Ingo Baab

Reputation: 608

You can easily do this with:

cat filename | sed 1d > filename_without_first_line

on the command line; or to remove the first line of a file permanently, use the in-place mode of sed with the -i flag:

sed -i 1d <filename>

Upvotes: 22

Hongbo Liu
Hongbo Liu

Reputation: 3072

Could use vim to do this:

vim -u NONE +'1d' +'wq!' /tmp/test.txt

This should be faster, since vim won't read whole file when process.

Upvotes: 6

Tim
Tim

Reputation: 17

If what you are looking to do is recover after failure, you could just build up a file that has what you've done so far.

if [[ -f $tmpf ]] ; then
    rm -f $tmpf
fi
cat $srcf |
    while read line ; do
        # process line
        echo "$line" >> $tmpf
    done

Upvotes: 0

serup
serup

Reputation: 3830

should show the lines except the first line :

cat textfile.txt | tail -n +2

Upvotes: 8

Nasri Najib
Nasri Najib

Reputation: 1291

For those who are on SunOS which is non-GNU, the following code will help:

sed '1d' test.dat > tmp.dat 

Upvotes: 86

alexis
alexis

Reputation: 50220

You can edit the files in place: Just use perl's -i flag, like this:

perl -ni -e 'print unless $. == 1' filename.txt

This makes the first line disappear, as you ask. Perl will need to read and copy the entire file, but it arranges for the output to be saved under the name of the original file.

Upvotes: 11

crydo
crydo

Reputation:

How about using csplit?

man csplit
csplit -k file 1 '{1}'

Upvotes: 5

EvilTeach
EvilTeach

Reputation: 28882

Would using tail on N-1 lines and directing that into a file, followed by removing the old file, and renaming the new file to the old name do the job?

If i were doing this programatically, i would read through the file, and remember the file offset, after reading each line, so i could seek back to that position to read the file with one less line in it.

Upvotes: -1

Robert Gamble
Robert Gamble

Reputation: 109132

As Pax said, you probably aren't going to get any faster than this. The reason is that there are almost no filesystems that support truncating from the beginning of the file so this is going to be an O(n) operation where n is the size of the file. What you can do much faster though is overwrite the first line with the same number of bytes (maybe with spaces or a comment) which might work for you depending on exactly what you are trying to do (what is that by the way?).

Upvotes: 11

Brent
Brent

Reputation: 16869

Since it sounds like I can't speed up the deletion, I think a good approach might be to process the file in batches like this:

While file1 not empty
  file2 = head -n1000 file1
  process file2
  sed -i -e "1000d" file1
end

The drawback of this is that if the program gets killed in the middle (or if there's some bad sql in there - causing the "process" part to die or lock-up), there will be lines that are either skipped, or processed twice.

(file1 contains lines of sql code)

Upvotes: 1

paxdiablo
paxdiablo

Reputation: 882296

No, that's about as efficient as you're going to get. You could write a C program which could do the job a little faster (less startup time and processing arguments) but it will probably tend towards the same speed as sed as files get large (and I assume they're large if it's taking a minute).

But your question suffers from the same problem as so many others in that it pre-supposes the solution. If you were to tell us in detail what you're trying to do rather then how, we may be able to suggest a better option.

For example, if this is a file A that some other program B processes, one solution would be to not strip off the first line, but modify program B to process it differently.

Let's say all your programs append to this file A and program B currently reads and processes the first line before deleting it.

You could re-engineer program B so that it didn't try to delete the first line but maintains a persistent (probably file-based) offset into the file A so that, next time it runs, it could seek to that offset, process the line there, and update the offset.

Then, at a quiet time (midnight?), it could do special processing of file A to delete all lines currently processed and set the offset back to 0.

It will certainly be faster for a program to open and seek a file rather than open and rewrite. This discussion assumes you have control over program B, of course. I don't know if that's the case but there may be other possible solutions if you provide further information.

Upvotes: 15

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