Reputation: 3
Fairly new to C and am trying to parse input from a file. I have no problems getting the operation and address fields but I am getting the value "32767" for the size field.
Here is the code causing issues:
#include <stdio.h>
#include <string.h>
void read_file(char *filename)
{
// operation field, address field, size field
FILE *file = fopen(filename, "r");
char buff[25];
char operation;
long address;
int size;
char *cur_trace = fgets(buff, 25, file);
while (cur_trace) {
// read indivdual fields of trace
// if cur_trace[0] == I then ignore line
if (cur_trace[0] != 'I') {
sscanf(cur_trace, " %c %lx[^,]%*c%u", &operation, &address, &size);
printf("operation: %c\n address: %lx\n size: %u\n", operation, address, size);
}
cur_trace = fgets(buff, 25, file);
}
}
int main(int argc, char const *argv[])
{
read_file("tester.txt");
return 0;
}
and here is the input text I am reading. All lines beginning with 'I' are being ignored.
I 0400d7d4,8
M 0421c7f0,4
L 04f6b868,8
S 7ff0005c8,8
Upvotes: 0
Views: 1671
Reputation: 2316
The problem is that your format string is not parsing the 3rd argument &size, because of the format string.
The 32767 value is just uninitialized junk.
You need to check that sscanf returns 3 so that all arguments are accounted for.
Upvotes: 0
Reputation: 409176
The brackets is not a generic part of the format string, it's part of a specific scanf
format code to read strings. It can't just be placed anywhere as a sort of pattern, or used for any other format.
And by the way, reading hexadecimal values will stop at the first non-hexadecimal character, so you don't need it anyway. Just doing e.g.
sscanf(cur_trace, " %c %lx,%u", &operation, &address, &size);
should be enough (if the types of the variables are correct).
Upvotes: 2