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phpmathdivisionmodulus
Sinister Beard
Sinister Beard

Reputation: 3680

How to test if $a is divisible by $b when $b is larger than $a

I'm trying to work out if one string, $a, is divisible by another, $b.

All of the examples I can find tell me to use modulus, e.g.:

if(($a %$b) == 0) : echo "Is dividible" ; endif;

However, because modulus returns the remainder of the calculation, this doesn't work if $b is larger than $a, because there's still no remainder.

How do I check divisibility where $b is sometimes (but not always) larger than $a?

Upvotes: 0

Views: 146

Answers (5)

Ashutosh Rai
Ashutosh Rai

Reputation: 457

Try this it should work:

$a = 7;
$b = 14;

//echo ( ($a > $b) && ( ($a % $b) == 0) ) ? "is divisible":"no divisible";

echo ( ($a < $b) && (($b % $a) == 0) ) ? "Is dividible" : "Is not divisable" ;

Upvotes: 0

Oliver Williams
Oliver Williams

Reputation: 6354

why don't you do this as a function:

function isDivisible($smaller,$bigger){
    //handle division by zero, and hmm.. let's cover negative numbers too
    if($smaller<=0) return false;
    if($smaller>$bigger) return false;
    return !($bigger % $smaller);
}

The negation ! should be a working and elegant way to handle it.

Upvotes: 2

Sugumar Venkatesan
Sugumar Venkatesan

Reputation: 4038

if($a==$b)
{echo "divisible a and b are equal";
}
else if($a>$b){
   if(($a %$b) == 0) : echo "Is dividible" ; endif;    
}
else{
echo "\$b is either large or equal to \$a";
 }

Upvotes: 0

wkdmarty
wkdmarty

Reputation: 201

How about:

echo ( ($a < $b) && (($a % $b) == 0) ) ? "Is dividible" : "Is not divisable" ;

Upvotes: 1

Rajveer gangwar
Rajveer gangwar

Reputation: 735

You can use ternary operator as example given below

(($a%$b)==0)?echo "Is divisible": echo "not divisible";

Upvotes: -1

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