CODEWITHSUNDEEP
phpdatetimedatediff
Syxmoke
Syxmoke

Reputation: 45

Why the difference between two DateTime objects does not work?

I've got a problem with my "DateTime difference code":

$timeStart = new DateTime('2015-11-28');
$timeEnd = new DateTime('2016-11-28');
$interval = $timeEnd->diff($timeStart);
$result = $interval->format('%d');

echo $result." day(s)";

When I visualize $result, PHP show me 0. But between those two dates there are more days than 0 day...

php does not calculate the difference between two dates that are not in the same year?

Upvotes: 3

Views: 170

Answers (2)

felipsmartins
felipsmartins

Reputation: 13549

Okay, I'm aware the answer was given already. But below is just a bit explanation.

In fact, DateInterval::format() does makes sense when you have a fixed amount of time (in years, months, days, hours), like this:

$interval = new DateInterval('P2Y4DT6H8M');
echo $interval->format('%d days');

That isn't your case!
where you have a relative time (2016-11-28 related to 2015-11-28) at all. In this specific case you want the days amount past since 28-11-2015.
That's why DateInterval::days (DateTime::diff() returns a DateInterval object) makes sense:

$start = new DateTime('2015-11-28');
$end   = new DateTime('2016-12-28');

var_dump($end->diff($start)->days);

Upvotes: 1

Jonnix
Jonnix

Reputation: 4187

Because there are 0 days difference. There is however a 1 year difference. If you changed %d to %y you'd get 1. So there's a difference of 1 year, 0 months and 0 days.

What you can use instead is the days property on DateInterval, as such:

$result = $interval->days;

Upvotes: 3

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