Reputation: 2164
This might be fairly easy but can't seem to figure it out.
This is what I want to get;
$t = 12:00
$todaysdate = 2015-11-30
I want to get $tomorrowsdate
with $t
appended to it
$tomorrowsdate = 2015-12-01 12:00
So basically I want to be able to add a given time to next day.
Upvotes: 0
Views: 38
Reputation: 186
Incase you want to use object oriented style use the following;
$today = new DateTime(); //today (2015-12-29)
$tommorow = $today->add(new DateInterval('P1D')); // add one day
echo $tommorow->format('Y-m-d H:i'); // echo results in desired format eg. 2015-12-30 12:36
// incase that 12:00 is important..
$tommorow->setTime(12,0);
echo $tommorow->format('Y-m-d H:i'); // 2015-12-30 12:00
Upvotes: 0
Reputation: 820
It's important to define them as a string if you wanna use strtotime
. Otherwise, you will get freaky results e.g. the year 1970 ;)
$t = '12:00';
$todaysdate = '2015-11-30';
$tomorrowsdate = date('Y-m-d', strtotime("{$todaysdate} + 1 day")) . " {$t}";
echo $tomorrowsdate;
Upvotes: 1