Reputation: 1
I am trying to replace all escaped characters \" in a string with "" but not if \" is preceded by a \
So that input such as:
So far I have
$ echo sed -e 's/\([^\]\)\\"/\1""/;s/^\\"/""/'
but in the case of
$ echo '\"\"\"\"\"' | sed -e 's/\([^\]\)\\"/\1""/;s/^\\"/""/'`
I am getting incorrect results.
Any help would be appreciated.
Upvotes: 0
Views: 115
Reputation: 1
Using a sed loop will allow not having to pick a unique replacement string for an unknown dataset.
sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
$ echo '\"\"\"\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g;t inner'
""""""""
$ echo '\"\\"\"\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
""\\"""""
$ echo '\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
""
$ echo '\"\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
""""
$ echo '\\"\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
\\"""
$ echo '\"\\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
""\\"
$ echo '\\\\\\\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
\\\\\\\"
Upvotes: 0
Reputation: 58371
This might work for you (GNU sed):
sed 's/\\\\"/\n/g;s/\\"/""/g;s/\n/\\\\"/g' file
Replace all occurances of the string you want untouched by something else (\n
is a good choice), replace the string you want changed globally, reinstate the first set of strings.
Upvotes: 1
Reputation: 28083
How about this:
#!/bin/bash
function myreplace {
echo "$1" | sed -e "s/[\\]\"/MYDUMMY/g" \
-e 's/\\MYDUMMY/\\\\"/g' \
-e 's/MYDUMMY/""/g'
}
myreplace '\"\"\"\"'
myreplace '\"\\"\"\"'
myreplace '\"'
myreplace '\"\"'
myreplace '\\"\"'
myreplace '\"\\"'
myreplace '\\\\\\\"'
Executing the script above results in:
""""""""
""\\"""""
""
""""
\\"""
""\\"
\\\\\\\"
Upvotes: 0