CODEWITHSUNDEEP
java
user5624516
user5624516

Reputation: 91

The method println(int) in the type PrintStream is not applicable for the arguments (String, int, int, int)

public static void main(String[] args) {
    int num1 = 1;
    int num2 = 1;
    int result = num1 * num2; 
    System.out.println("%d x %d = %d\n",num1,num2,result);
}

I am trying to printout a form like "1 * 10 = 10". However I get an error:

The method println(int) in the type PrintStream is not applicable for the arguments (String, int, int, int)".

I don't know what's the problem and how should I change it?

Upvotes: 8

Views: 28764

Answers (8)

gabriel eliezer
gabriel eliezer

Reputation: 1

System.Out.println - does not accept arguments %d among others

System.Out.format - You need to use format instead of println

stays like this:

System.out.format("%d x %d = %d",num1, num2, result);

Upvotes: 0

Tekilu Yewubdar
Tekilu Yewubdar

Reputation: 1

enter code here


    int first = 20;
    int second = 30;
    System.out.println("before swap");
    System.out.println("first value :" +first);
    
    System.out.println("second value: " +second);
    first = first - second;
    second = first + second;
    first = second - first;
    
    System.out.println("after swap");
  System.out.println("first value: " +first);
    
    System.out.println("second value: " +second);

remove comma from the print statement

Upvotes: -1

Mayuso
Mayuso

Reputation: 1329

Try 

System.out.println(num1+" x "+num2+" = "+result+"\n");

UPDATE: Some of you are saying this concatenation method is slower than other methods. You are right, it is slower, but does it really matter for this example?

This method is usually used to debug, not as part of the final code, and usually only once or twice on the whole code.

Faster method:

System.out.printf("%d x %d = %d\n",num1,num2,result);

Upvotes: 14

Abhijeet
Abhijeet

Reputation: 8771

println as documented here currently accepts 0 or 1 arguments, reason for the mentioned error.

You need to either concatenate or use String Format to format the result if you intend to use println(only):

  • String Format: System.out.println(String.format("%d x %d = %d\n",num1,num2,result));

  • String Concatenation using StringBuffer: StringBuffer resltBuffer = new StringBuffer(num1).append(" x ").append(num2).append(" = ").append(result); System.out.println(resltBuffer.toString());

Upvotes: 0

Vistari
Vistari

Reputation: 707

Have you tried using system.out.format like this:

System.out.format("%s x %s = %s\n",num1,num2,result);

Your current solution using println isn't working as println cannot format text output in this way, you would have to (as others have said) concatenate the string using the "+" operator. It's slower in most cases but for debugging purposes I shouldn't imagine it's much of a problem either way.

Upvotes: 7

Haseeb Anser
Haseeb Anser

Reputation: 504

One of the simple way is that you can use the concatenation operation '+' instead of ',' to print 

 public static void main(String[] args) {
        // TODO Auto-generated method stub
        int result = 0;
        for(int num1 = 1;num1 < 10;num1++){
            for(int num2 = 1;num2 <10;num2++){
                result = num1 * num2; 
                System.out.println(num1+"x"+num2+"="+result);
            }
        }
    }

}

Upvotes: 4

Felix Gerber
Felix Gerber

Reputation: 1651

The Method your using (System.out.println) isn't made for multiple parameters. By using , you try to give it multiple parameters. You need the +-operator.

Applied to your code it should look like that:

System.out.println(num1 + " x " + num2 + " = " + result);

Maybe you should look at this. This is the Documentation of PrintStream. As you can see there is no method like you are using it(System.out.println(String, Int, Int ,Int);).

Upvotes: 4

ParkerHalo
ParkerHalo

Reputation: 4430

There's a printf(...) method in System.out!

System.out.printf("%d x %d = %d\n",num1,num2,result);

Upvotes: 6

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