CODEWITHSUNDEEP
cocoaunixapplescript
DisplayName
DisplayName

Reputation: 209

Cant make "path" into type real

I have a script file inside the "Resources" folder, I am trying to run it like this

set scriptpath to (path to current application as text)
set scripty to do shell script scriptpath/Contents/Resources/moveskript & variable1 & variable2 with administrator privileges

But it tells me this:

2015-12-01 12:19:47.208 Move[16404:534222] *** -[AppDelegate mybuttonhandler:]: Can’t make "(path.app):" into type real. (error -1700)

Upvotes: 0

Views: 160

Answers (2)

Darrick Herwehe
Darrick Herwehe

Reputation: 3722

Your problem is this part:

... do shell script scriptpath/Contents/Resources/moveskript ...

To concatenate a literal string to a variable, you need wrap the string in quotes and use &:

do shell script scriptpath & "/Contents/Resources/moveskript"

Because the slashes aren't within quotes, Applescript recognizes them as a division symbol, so it thinks you are trying to divide scriptpath by Contents. That is why it is trying to coerce the scriptpath variable into type real. But, since it's a string with letters, Applescript is unable to convert it.

Upvotes: 0

vadian
vadian

Reputation: 285082

Two issues:

  • You're mixing up HFS paths (colon separated) and POSIX paths (slash separated)
  • current application is the current AppleScript runner, not the current script / application.

Use Cocoa methods to get the path to the resources folder.

set resourceFolder to current application's NSBundle's mainBundle's resourcePath()
set scriptpath to (resourceFolder's stringByAppendingPathComponent:"moveskript") as text
set scripty to do shell script quoted form of scriptpath & space & quoted form of variable1 & space & quoted form of variable2 with administrator privileges

Consider that shell parameters must be separated by space characters (between scriptpath and variable1 and between variable1 and variable2) and space characters within parameters must be escaped.

Upvotes: 1

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