CODEWITHSUNDEEP
pythonparamiko
Nikolas Stephan
Nikolas Stephan

Reputation: 1290

Suppressing Output of Paramiko SSHClient Class

When I call the connect function of the Paramiko SSHClient class, it outputs some log data about establishing the connection, which I would like to suppress.

Is there a way to do this either through Paramiko itself, or Python in general?

Upvotes: 4

Views: 8285

Answers (3)

Aaron Bredon
Aaron Bredon

Reputation: 11

You can do something like this:

paramiko_logger = logging.getLogger("paramiko")
paramikoHandler = logging.NullHandler()  # no handler for summary messages
paramiko_logger.addHandler(paramikoHandler)

Basically, this accesses/creates the "paramiko" logger, and sets it to use a Null handler.

Paramiko is following bad form by logging errors to output/error regardless of whether they are caught or not.

Upvotes: 0

JimB
JimB

Reputation: 109325

Paramiko doesn't output anything by default. You probably have a call to the logging module, setting a loglevel that's inherited when paramiko sets up it's own logging.

If you want to get at the paramiko logger to override the settings:

logger = paramiko.util.logging.getLogger()

There's also a convenience function to log everything to a file:

paramiko.util.log_to_file('filename.log')

Upvotes: 7

M. Utku ALTINKAYA
M. Utku ALTINKAYA

Reputation: 2272

I don't know what Paramiko is, and there must be a log level setting for sure, but if you are desperate and looking for a temporary solution and if your app is single threaded

import sys
dev_null = sys.stdout = sys.stderr = open('/dev/null', 'w')
try:
.
. connect()
.
finally:
  dev_null.close()

you can use StringIO for output also, if you are on an OS not have a '/dev/null'

Upvotes: 0

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