Reputation: 2862
I am trying to send an image with PHP (on server side) to my iOS app, so that I can display it in a UIImageView.
My server side code is:
<?php
header("Content-Type: image/jpeg"); //if your data is format jpeg
$username = $_POST['username'];
$count = $_POST['count'];
$base64string = base64_encode(file_get_contents("images/".$username."/".$count."/".$username."file".$count.".jpeg"));
echo $base64string;
?>
I receive the image with this code in my iOS app:
NSString * uploadURL = @"http://192.168.1.4/getimage.php";
NSLog(@"uploadImageURL: %@", uploadURL);
NSString *queryStringss = [NSString stringWithFormat:@"%@", uploadURL];
queryStringss = [queryStringss stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
manager.responseSerializer=[AFJSONResponseSerializer serializerWithReadingOptions:NSJSONReadingAllowFragments];
manager.responseSerializer.acceptableContentTypes = [manager.responseSerializer.acceptableContentTypes setByAddingObject:@"text/html"];
manager.responseSerializer.acceptableContentTypes = [manager.responseSerializer.acceptableContentTypes setByAddingObject:@"text/plain"];
manager.responseSerializer.acceptableContentTypes = [manager.responseSerializer.acceptableContentTypes setByAddingObject:@"image/jpeg"];
NSUserDefaults *userdefaults = [NSUserDefaults standardUserDefaults];
NSString *usernameEncoded = [marker.title stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSDictionary *params = @{@"username": usernameEncoded, @"count": [object valueForKey:@"count"]};
[manager POST:queryStringss parameters:params success:^(AFHTTPRequestOperation * _Nonnull operation, id _Nonnull responseObject) {
NSLog(@"Success: %@ ***** %@", operation.responseString, responseObject);
NSData *decodedData = [[NSData alloc] initWithBase64EncodedString:responseObject options:0];
image.image = [UIImage imageWithData:decodedData scale:300/2448];
[self.view addSubview:image];
}
failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@ ***** %@", operation.responseString, error);
}];
When I run the code - it hits the failure block with an error that reads as the base64 encoded "string" (image) that I am sending:
2015-12-03 01:19:15.655 sneek[6261:1952572] Error: /9j/4AAQSkZJRgABAQAASABIAAD/4QBYRXhpZgAATU0AKgAAAAgAAgESAAMAAAABAAYAAIdpAAQAAAABAAAAJgAAAAAAA6ABAAMAAAABAAEAAKACAAQAAAABAAAMwKADAAQAAAABAAAJkAAAAAD/7QA4UGhvdG9zaG9wIDMuMAA4QklNBAQAAAAAAAA4QklNBCUAAAAAABDUHYzZjwCyBOmACZjs+EJ+/8AAEQgJkAzAAwEiAAIRAQMRAf/EAB8AAAEFAQEBAQEBAAAAAAAAAAABAgMEBQYHCAkKC//EALUQAAIBAwMCBAMFBQQEAAABfQECAwAEEQUSITFBBhNRYQcicRQygZGhCCNCscEVUtHwJDNicoIJChYXGBkaJSYnKCkqNDU2Nzg5OkNERUZHSElKU1RVVldYWVpjZGVmZ2hpanN0dXZ3eHl6g4SFhoeIiYqSk5SVlpeYmZqio6Slpqeoqaqys7S1tr
... (very long) ...
Error Domain=NSCocoaErrorDomain Code=3840 "Invalid value around character 0." UserInfo={NSDebugDescription=Invalid value around character 0.}
What am I doing incorrectly?
Upvotes: 1
Views: 147
Reputation: 437622
You've specified AFJSONResponseSerializer
even though it's not JSON. Sure, you've overridden acceptableContentTypes
, but that doesn't stop it from trying to parse JSON in the response.
I'd use AFHTTPResponseSerializer
and then lose the acceptableContentTypes
.
By the way, I wouldn't use image/jpeg
for a base64-encoded response, because it's text, not a jpeg. If you're going to return a raw base64-string, you might use application/text
or something like that.
Or, better, change your PHP to actually return JSON (because that will make it easier to parse the response) and stay with AFJSONResponseSerializer
(but lose the acceptableContentTypes
once you fix the header) and then you can grab the base64 string from response[@"image"]
.
<?php
header("Content-Type: application/json");
$username = $_POST['username'];
$count = $_POST['count'];
$base64string = base64_encode(file_get_contents("images/".$username."/".$count."/".$username."file".$count.".jpeg"));
echo json_encode(array("image" => $base64string));
?>
Or, use AFImageResponseSerializer
and change the PHP to return the image:
<?php
header("Content-Type: image/jpeg"); //if your data is format jpeg
$username = $_POST['username'];
$count = $_POST['count'];
$contents = file_get_contents("images/".$username."/".$count."/".$username."file".$count.".jpeg"));
echo $contents;
?>
Upvotes: 1