CODEWITHSUNDEEP
java
VicX
VicX

Reputation: 711

Is there a way to tell Java compiler not to auto box my primitive type

For example, here are two java methods

void test(int... values){}

And

void test(Object... values){}

If I make a call with arguments (1,2,3), there will be a compile error.

Also, I just need the facilities of java varargs, and can not declare my methods with argments int[] or Object[].

Is it possible?

Upvotes: 0

Views: 66

Answers (2)

yshavit
yshavit

Reputation: 43391

You can always create the array explicitly:

foo.test(new int[] { 1, 2, 3 });

This works precisely as the vararg method would, so the bytecode won't even know the difference, and it'll resolve to the int... overload.

The above is essentially equivalent to creating a variable for the int[], and passing that in:

int[] ints = { 1, 2, 3 };
foo.test(ints);

There isn't any other way to tell the compiler which overload you want.

Upvotes: 2

Patricia Shanahan
Patricia Shanahan

Reputation: 26185

If you explicitly convert and cast to make the actual arguments exactly match one of the formal argument lists, there is no ambiguity:

public class Test {
  public static void main(String[] args) {
    test(new int[] { 1, 2, 3 });
    test((Object[]) new Integer[] { 1, 2, 3 });
  }

  public static void test(int... values) {
    System.out.println("int version called");
  }

  public static void test(Object... values) {
    System.out.println("Object version called");
  }

}

Upvotes: 0

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