CODEWITHSUNDEEP
listpython-2.7indexingmax
BeGlad
BeGlad

Reputation: 25

How do you count how many maximum values there are in a list?

Lets say I have the list below:

list1=[1,2,4,6,8,3,2,5,8,4,2]

I want to return the integer, 2, because 8 is the maximum value and there are two 8s in the list. How can I do this? Edit: I also want to assume that the maximum number in the list can be any negative or non-negative number including zero.

Upvotes: 0

Views: 402

Answers (3)

Mahadeva
Mahadeva

Reputation: 1637

Well you can use something like this:

list1=[1,2,4,6,8,3,2,5,8,4,2]
print list1.count(max(list1))

Upvotes: 1

Mayur Koshti
Mayur Koshti

Reputation: 1862

>>> list1=[1,2,4,6,8,3,2,5,8,4,2]
>>> x = max(list1)
>>> l = []
>>> for i in list1:
    if i == x:
        l.append(i)


>>> l
[8, 8]
>>> len(l)
2

OR

>>> list1=[1,2,4,6,8,3,2,5,8,4,2]
>>> x = max(list1)
>>> result = len(filter(lambda i: i == x, list1))
>>> result
2

Upvotes: 0

vinllen
vinllen

Reputation: 1459

ans = 0
mx = 0
for x in list1:
    if x > mx:
        mx = x
        ans = 1
    elif x == mx :
        ans += 1

print ans

assume max number is bigger than 0, otherwise you should initial mx with the negative infinity

Upvotes: 0

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