CODEWITHSUNDEEP
objective-crandomfloating-point
Roman
Roman

Reputation: 385

How to create a random float in Objective-C?

I'm trying to create a random float between 0.15 and 0.3 in Objective-C. The following code always returns 1:

int randn = (random() % 15)+15;
float pscale = (float)randn / 100;

What am I doing wrong?

Upvotes: 35

Views: 38527

Answers (8)

Boris
Boris

Reputation: 689

Here is a function

- (float)randomFloatBetween:(float)smallNumber and:(float)bigNumber {
    float diff = bigNumber - smallNumber;
    return (((float) (arc4random() % ((unsigned)RAND_MAX + 1)) / RAND_MAX) * diff) + smallNumber;
}

Upvotes: 68

Ky -
Ky -

Reputation: 32083

To add to @Caladain's answer, if you want the solution to be as easy to use as rand(), you can define these:

#define randf() ((CGFloat)rand() / RAND_MAX)
#define randf_scaled(scale) (((CGFloat)rand() / RAND_MAX) * scale)

Feel free to replace CGFloat with double if you don't have access to CoreGraphics.

Upvotes: 0

jose920405
jose920405

Reputation: 8049

Easiest.

+ (float)randomNumberBetween:(float)min maxNumber:(float)max
{
    return min + arc4random_uniform(max - min + 1);
}

Upvotes: 2

melovje
melovje

Reputation: 20

I ended up generating to integers one for the actual integer and then an integer for the decimal. Then I join them in a string then I parse it to a floatvalue with the "floatValue" function... I couldn't find a better way and this works for my intentions, hope it helps :)

int integervalue = arc4random() % 2;
int decimalvalue = arc4random() % 9;   
NSString *floatString = [NSString stringWithFormat:@"%d.%d",integervalue,decimalvalue];
float randomFloat = [floatString floatValue];

Upvotes: -5

malex
malex

Reputation: 10096

Using srandom() and rand() is unsafe when you need true randomizing with some float salt.

On MAC_10_7, IPHONE_4_3 and higher you can use arc4random_uniform(upper_bound)*. It allows to generate true random integer from zero to *upper_bound*.

So you can try the following

u_int32_t upper_bound = <some big enough integer>;

float r = 0.3 * (0.5 + arc4random_uniform(upper_bound)*1.0/upper_bound/2);

Upvotes: 0

Caladain
Caladain

Reputation: 4934

Try this: 

 (float)rand() / RAND_MAX

Or to get one between 0 and 5:

 float randomNum = ((float)rand() / RAND_MAX) * 5;

Several ways to do the same thing.

Upvotes: 21

dreamlax
dreamlax

Reputation: 95335

Your code works for me, it produces a random number between 0.15 and 0.3 (provided I seed with srandom()). Have you called srandom() before the first call to random()? You will need to provide srandom() with some entropic value (a lot of people just use srandom(time(NULL))).

For more serious random number generation, have a look into arc4random, which is used for cryptographic purposes. This random number function also returns an integer type, so you will still need to cast the result to a floating point type.

Upvotes: 3

Lou Franco
Lou Franco

Reputation: 89172

  1. use arc4random() or seed your random values

  2. try

    float pscale = ((float)randn) / 100.0f;

Upvotes: 4

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