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phpisset
Stuart
Stuart

Reputation: 39

PHP - How do I correctly use a "if(isset() && != NULL) || (isset() && != NULL)" statement?

Hi I am having trouble with the OR operators in this function and I am not sure why?

<?php if(isset($value['instagram_id']) && $value['instagram_id'] != NULL) || (isset($value['facebook_id']) && $value['facebook_id'] != NULL) || (isset($value['soundcloud_id']) && $value['soundcloud_id'] != NULL) || (isset($value['twitter_id']) && $value['twitter_id'] != NULL) || (isset($value['youtube_id'])) && $value['youtube_id'] != NULL) { ?>

Can someone please shed some light on what I am doing wrong?

Upvotes: 0

Views: 1261

Answers (3)

Maneesh
Maneesh

Reputation: 51

if ($value['instagram_id'],  $value['instagram_id'])) {
}

This will return true only if all arguments to isset() are set and do not contain null.

Upvotes: 0

Andrew
Andrew

Reputation: 2975

well....if you want to evaluate all the statement in one condition, then you can reduce your if statement to below

if(!empty($value['instagram_id']) || !empty($value['facebook_id']) || !empty($value['soundcloud_id']) || !empty($value['twitter_id']) || !empty($value['youtube_id']) ) {

}

from the Docs

empty() is essentially the concise equivalent to !isset($var) || $var == false

!empty will also evaluate null as false

Upvotes: 2

Nikolay Yenbakhtov
Nikolay Yenbakhtov

Reputation: 443

Try this:

<?php 
    if((isset($value['instagram_id']) && $value['instagram_id']) ||
    (isset($value['facebook_id']) && $value['facebook_id']) ||
    (isset($value['soundcloud_id']) && $value['soundcloud_id']) ||
    (isset($value['twitter_id']) && $value['twitter_id']) ||
    (isset($value['youtube_id']) && $value['youtube_id'])){
        ... //TODO something
    }   
?>

Upvotes: 0

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