CODEWITHSUNDEEP
java
SamHat
SamHat

Reputation: 29

Output Of A Series

I am trying to write a Java program to get the output of this series:

series

So I have done this:

import java.util.Scanner;

public class ICSE2007_Pg111 {

    public static void main() {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter th elimit");
        int n = sc.nextInt();

        double add = 0;
        double mult = 1;
        double divide = 0;
        double total = 0;
        for (int i = 2; i <= n; i++) {
            for (int x = 1 ; x <= i; x++) {
                add += x;
                mult *= x;
            }

            divide = add / mult;
            total += divide;
        }
        System.out.println("The resultant sum = " + total);
    }
}

I think this code is correct. However, for the value of n = 3 the correct output should be 2.916666666666666666, but I am getting 2.25. If someone could please pin point the error.

Upvotes: 2

Views: 50

Answers (2)

Navin Gupta
Navin Gupta

Reputation: 803

You can do this in optimized way in one loop

float sum = 1;
float mul = 1;
float res = 0;
for(int i = 2;i<=n;i++) {
    sum = sum+i;
    mul = mul*i;
    res = res+(sum/mul);
}

Upvotes: 0

Eran
Eran

Reputation: 393771

You forgot to reset add and mult before the inner loop :

   for(i = 2;i<=n;i++) {
        add = 0; 
        mult = 1;
        for(x =1 ;x<=i;x++)
        {
            add +=x;
            mult *= x;

        }
        ...

P.S. based on your image, for n=3 you should get 2.5.

Upvotes: 2

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