CODEWITHSUNDEEP
javascriptlodash
TheWebs
TheWebs

Reputation: 12923

Search through an array of objects looking for non empty objects JS

At the core of the problem I have:

[
  {amount: 0, name: "", icon: "", description: ""} // default object added to array
  {amount: 1, name: "kjfhdkfjh", icon: "67", description: "dasdasd"}
]

I want to know how to use lodash find such that, as long as any key has a value other then 0 or "" we are not considered "empty".

So in this case lodash find would return:

[
  {amount: 1, name: "kjfhdkfjh", icon: "67", description: "dasdasd"}
]

Or it would return undefined.

What I have is:

lodashFind(theArray, function(obj){
   // Now what? How do I go through the objects? 
});

I am not sure how to go through objects saying, as long as there is no 0 for amount and no string has "" then return that object.

Ideas?

Upvotes: 1

Views: 1360

Answers (2)

Tamas Hegedus
Tamas Hegedus

Reputation: 29906

Use _.filter, _.some, _.all or _.negate of lodash to achieve this:

var data = [
    { name:'a', age:0 },
    { name:'b', age:1 },
    { name:'',  age:0 }
];

// lists not empty objects (with at least not empty field)
console.log(_.filter(data, _.some));
// outputs [{name:'a',age:0},{name:'b',age:1}]

// lists 'full' objects (with no empty fields)
console.log(_.filter(data, _.all));
// outputs [{name:'b',age:1}]

// lists 'empty' objects (with only empty fields)
console.log(_.filter(data, _.negate(_.some)));
// outputs [{name:'',age:0}]

_.some and _.all search for truthy values, '' and 0 is not truthy. Namely, the following JavaScript values are falsy: false, 0, '', null, undefined, NaN. Every other value is truthy.

Upvotes: 4

adeneo
adeneo

Reputation: 318182

Using just regular javascript, this is quite easy as well, just filter the array based on the objects values etc, like this

var arr = [
  {amount: 0, name: "", icon: "", description: ""},
  {amount: 1, name: "kjfhdkfjh", icon: "67", description: "dasdasd"}
]

arr = arr.filter(function(o) {
  return Object.keys(o).filter(function(key) {
    return o[key] != 0 && o[key].toString().trim().length > 0;
  }).length > 0;
});

FIDDLE

Upvotes: 0

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