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javaarrays
Panagiotis
Panagiotis

Reputation: 511

Checking if an array contains one integer value

Don't want to use loops. I tried the below code but it doesn't work for primitive types.

if ( Arrays.asList( myMatrix ).contains( -1 ) )
{
    // do something
}

What shall be done here?

Upvotes: 1

Views: 3460

Answers (3)

Thilo
Thilo

Reputation: 262534

Java should really have a method contains on java.util.Arrays.

Commons Lang has it, for example.

So I would either find it in the libraries I already use, or make a static helper method myself (with a simple loop inside).

Upvotes: 3

Pshemo
Pshemo

Reputation: 124235

You can't avoid iteration in your code since we need some way to test all elements in your array (at least until we will find the one we are looking for). But to make your life easier create some additional utility method like (name could be probably better/more descriptive) public static boolean contains(int[] array, int element) which will handle iteration for us. Then simply use it like if(contains(matrix, -1)).

In Java 8 you could use IntStream which handles int[] myMatrix array correctly (like Array.asList handles Integer[] myMatrix).

So as condition you could use something like:

IntStream.of(myMatrix).anyMatch(i -> i == -1)

Upvotes: 3

Hovercraft Full Of Eels
Hovercraft Full Of Eels

Reputation: 285405

"I don't want to use loops" -- you can't always get what you want, and in fact in this situation, use a loop.

Upvotes: 2

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