Reputation: 33813
I have two servers.
The first (Local) is the server which has the script.
The second (Remote) is the server which has uploaded files only (just for storage).
Now I'm confused about how to upload the files, and I have 2 ways and I don't know what the best one of them.
The ways:
Upload the file to the local server first and make all security operations like (check file size,file type, and so on), then upload again to the second server (remote server).
Upload the file to the second server (remote server) directly, and make all checks and security operations in there, then send the file information to the first server (local) to store the info into database.
I have tried to apply the second way, by send the file directly to the second server (remote server) and then after everything is ok, the second server (remote server) send to the first server (local) all information about the uploaded file by curl.
For example:
The following code written in file exists in php file in the second server (remote server).
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://localServer/script/receiveReques.php");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 2);
curl_setopt($ch, CURLOPT_TIMEOUT, 2);
curl_setopt($ch, CURLOPT_POST, 3);
curl_setopt($ch, CURLOPT_POSTFIELDS, array('fileName' => 'filename.zip', 'size' => 1000, 'path'=> 'http://remoteserver.com/files/filenmae.zip'));
curl_exec($ch);
curl_close($ch);
But the problem I don't know how to get the sent information.
The summary of my questions is:
Upvotes: 1
Views: 2303
Reputation: 18550
you have
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
all you need to do is use the data it returns
$data = curl_exec($ch);
all of the data is now in $data
Upvotes: 3