Reputation: 13760
I recently pointed a student doing work experience to an article about dumping a multiplication table to the console. It used a nested for loop and multiplied the step value of each.
This looked like a .NET 2.0 approach. I was wondering, with the use of Linq and extension methods,for example, how many lines of code it would take to achieve the same result.
Is the stackoverflow community up to the challenge?
The challenge: In a console application, write code to generate a table like this example:
01 02 03 04 05 06 07 08 09 02 04 06 08 10 12 14 16 18 03 06 09 12 15 18 21 24 27 04 08 12 16 20 24 28 32 36 05 10 15 20 25 30 35 40 45 06 12 18 24 30 36 42 48 54 07 14 21 28 35 42 49 56 63 08 16 24 32 40 48 56 64 72 09 18 27 36 45 54 63 72 81
As this turned into a language-agnostic code-golf battle, I'll go with the communities decision about which is the best solution for the accepted answer.
There's been alot of talk about the spec and the format that the table should be in, I purposefully added the 00 format but the double new-line was originally only there because I didn't know how to format the text when creating the post!
Upvotes: 18
Views: 3867
Reputation: 1420
BASH 53
for((i=1;i<10;i++));do seq -s' ' $i $i $((9*i));done
Upvotes: 0
Reputation:
C++ RANKING IN AT 99999TH PLACE (76 chars)
for(int i=1;i<=9;++i){cout<<i<<" "<<i+1<<i+2<<i+3<<i+4<<i+5<<i+6<<i+7<<i+8;}
Upvotes: 0
Reputation: 15829
↓1⇄.⇄^↓↻*;
This is using my own toy language stack-based language Repent (which I will release soon, once it is up to scratch). I am sad to see J beating it, because I designed it only to beat J, Perl and Golfscript at code golf.
V_1v.v^↓↻*;
Upvotes: 0
Reputation: 22443
C# - 117, 113, 99, 96, 95 89 characters
updated based on NickLarsen's idea
for(int x=0,y;++x<10;)
for(y=x;y<x*10;y+=x)
Console.Write(y.ToString(y<x*9?"00 ":"00 \n"));
99, 85, 82 81 characters
... If you don't care about the leading zeros and would allow tabs for alignment.
for(int x=0,y;++x<10;)
{
var w="";
for(y=1;++y<10;)
w+=x*y+" ";
Console.WriteLine(w);
}
Upvotes: 5
Reputation: 12389
JavaScript - with console - 65 chars
for(i=0,a='';++i<10;a+='\n')for(j=0;++j<10;a+=i*j);console.log(a)
JavaScript - with html - 68 chars
for(i=0,a='';++i<10;a+='\n')for(j=0;++j<10;a+=i*j);document.write(a)
Upvotes: 0
Reputation: 1108782
class M{public static void main(String[]a){for(int x,y=0,z=10;++y<z;System.out.println())for(x=0;++x<z;System.out.printf("%02d ",x*y));}}
More readable format:
class M{
public static void main(String[]a){
for(int x,y=0,z=10;++y<z;System.out.println())
for(x=0;++x<z;System.out.printf("%02d ",x*y));
}
}
Upvotes: 1
Reputation: 74
Haskell (not list comprehensions) 71 after import
It's a shame haskell doesn't have printf in it's prelude library but after importing in ghci 71 chars,the other haskell program was using list comprehensions:
Prelude> :module Text.Printf
Prelude Text.Printf> let r=[1..9]
Prelude Text.Printf> mapM_(\y->(mapM_(\x->printf"%02d "(x*y))r)>>(putStrLn ""))r
01 02 03 04 05 06 07 08 09
02 04 06 08 10 12 14 16 18
03 06 09 12 15 18 21 24 27
04 08 12 16 20 24 28 32 36
05 10 15 20 25 30 35 40 45
06 12 18 24 30 36 42 48 54
07 14 21 28 35 42 49 56 63
08 16 24 32 40 48 56 64 72
09 18 27 36 45 54 63 72 81
Upvotes: 0
Reputation: 125864
a=1:9;a'*a
a=1:9;disp(num2str(a'*a,'%.2d '))
Upvotes: 16
Reputation: 12320
for(;$x++<9;print"\n",$y=0)while($y++<9)printf("%02d ",$x*$y);
Upvotes: 1
Reputation: 54584
print(1 to 9 map(p=>1 to 9 map(q=>"%02d "format(p*q))mkString)mkString("\n"))
Sorry, I had to do this, the Scala solution by Malax was way too readable...
[Edit] For comprehension seems to be the better choice:
for(p<-1 to 9;q<-{println;1 to 9})print("%02d "format p*q)
[Edit] A much longer solution, but without multiplication, and much more obfuscated:
val s=(1 to 9).toSeq
(s:\s){(p,q)=>println(q.map("%02d "format _)mkString)
q zip(s)map(t=>t._1+t._2)}
Upvotes: 1
Reputation: 9635
for i in `seq 9`;do seq -w $i $i 99|sed 9q;done|column -c80
01 02 03 04 05 06 07 08 09
02 04 06 08 10 12 14 16 18
03 06 09 12 15 18 21 24 27
04 08 12 16 20 24 28 32 36
05 10 15 20 25 30 35 40 45
06 12 18 24 30 36 42 48 54
07 14 21 28 35 42 49 56 63
08 16 24 32 40 48 56 64 72
09 18 27 36 45 54 63 72 81
Upvotes: 0
Reputation: 304205
PROGRAM-ID.P.DATA DIVISION.WORKING-STORAGE SECTION.
1 I PIC 9.
1 N PIC 99.
PROCEDURE DIVISION.PERFORM 9 TIMES
ADD 1 TO I
SET N TO I
PERFORM 9 TIMES
DISPLAY N' 'NO ADVANCING
ADD I TO N
END-PERFORM
DISPLAY''
END-PERFORM.
Edit
PROGRAM-ID.P.DATA DIVISION.WORKING-STORAGE SECTION.
1 I PIC 9.
1 N PIC 99.
PROCEDURE DIVISION.
PERFORM B 9 TIMES
STOP RUN.
B.
ADD 1 TO I
set N to I
PERFORM C 9 TIMES
DISPLAY''.
C.
DISPLAY N" "NO ADVANCING
Add I TO N.
Upvotes: 4
Reputation: 4262
XQuery 1.0 (96 bytes)
string-join(for$x in 1 to 9 return(for$y in 1 to 9 return concat(0[$x*$y<10],$x*$y,' '),'
'),'')
Run (with XQSharp) with:
xquery table.xq !method=text
Upvotes: 1
Reputation: 16687
*/~1+i.9
Gives:
1 2 3 4 5 6 7 8 9 2 4 6 8 10 12 14 16 18 3 6 9 12 15 18 21 24 27 4 8 12 16 20 24 28 32 36 5 10 15 20 25 30 35 40 45 6 12 18 24 30 36 42 48 54 7 14 21 28 35 42 49 56 63 8 16 24 32 40 48 56 64 72 9 18 27 36 45 54 63 72 81
This solution found by @earl:
'r(0)q( )3.'8!:2*/~1+i.9
Gives:
01 02 03 04 05 06 07 08 09 02 04 06 08 10 12 14 16 18 03 06 09 12 15 18 21 24 27 04 08 12 16 20 24 28 32 36 05 10 15 20 25 30 35 40 45 06 12 18 24 30 36 42 48 54 07 14 21 28 35 42 49 56 63 08 16 24 32 40 48 56 64 72 09 18 27 36 45 54 63 72 81
Upvotes: 41
Reputation: 304205
This solution does print the leading zeros as per the spec.
print"(9(i3.2))",((i*j,i=1,9),j=1,9);end
Upvotes: 6
Reputation: 7238
var r=Enumerable.Range(1,9).ToList();
r.ForEach(i=>Console.WriteLine(r.Aggregate("",(a,b)=>a+=(i*b).ToString("00 "))));
Upvotes: 0
Reputation: 181785
01 02 03 04 05 06 07 08 09
02 04 06 08 10 12 14 16 18
03 06 09 12 15 18 21 24 27
04 08 12 16 20 24 28 32 36
05 10 15 20 25 30 35 40 45
06 12 18 24 30 36 42 48 54
07 14 21 28 35 42 49 56 63
08 16 24 32 40 48 56 64 72
09 18 27 36 45 54 63 72 81
Assuming that a trailing newline is wanted; otherwise, 251 chars.
* runs *
Upvotes: 14
Reputation:
while(++$x<10){$y=0;while(++$y<10)printf("%02d ",$x*$y);print"\n";}
Upvotes: 0
Reputation: 523334
r=[1..9]
s x=['0'|x<=9]++show x
main=mapM putStrLn[unwords[s$x*y|x<-r]|y<-r]
If double spacing is required (89 81 chars),
r=[1..9]
s x=['0'|x<=9]++show x
main=mapM putStrLn['\n':unwords[s$x*y|x<-r]|y<-r]
Upvotes: 3
Reputation: 21258
Common Lisp, 79 characters (including whitespace):
(dotimes (i 9) (dotimes (j 9) (format t "~2,'0d " (* (1+ i) (1+ j)))) (terpri))
With something approaching a more traditional formatting:
(dotimes (i 9)
(dotimes (j 9)
(format t "~2,'0d " (* (1+ i) (1+ j))))
(terpri))
Then there's a 106-character version showing off the power of the formatter:
(format t "~{~{~2,'0d~^ ~}~%~}"
(loop for i from 1 to 9
collect (loop for j from 1 to 9
collect (* i j))))
Upvotes: 0
Reputation: 304205
This method is two lines of input and only works in irb
(because irb gives us _
), but shortens the previous method by a scant 2 charcters.
1..9
_.map{|y|puts"%02d "*9%_.map{|x|x*y}}
(a=1..9).map{|y|puts"%02d "*9%a.map{|x|x*y}}
Ruby - 46 Chars
9.times{|y|puts"%02d "*9%(1..9).map{|x|x*y+x}}
Ruby - 47 Chars
And back to a double loop
(1..9).map{|y|puts"%02d "*9%(1..9).map{|x|x*y}}
Ruby - 54 chars!
Using a single loop saves a couple of chars!
(9..89).map{|n|print"%02d "%(n/9*(x=n%9+1))+"\n"*(x/9)}
Ruby - 56 chars
9.times{|x|puts (1..9).map{|y|"%.2d"%(y+x*y)}.join(" ")}
Upvotes: 3
Reputation: 31428
1.upto(9){|n|puts"%02d "*9%(n..81).step(n).to_a}
PS. With Wolfram Alpha it's 23 characters DS.
Upvotes: 0
Reputation: 15180
for($x=0;++$x<10;print"\n"){for($y=0;++$y<10;){printf("%02d ",$x*$y);}}
Output:
$ php -r 'for($x=0;++$x<10;print"\n"){for($y=0;++$y<10;){printf("%02d ",$x*$y);}}'
01 02 03 04 05 06 07 08 09
02 04 06 08 10 12 14 16 18
03 06 09 12 15 18 21 24 27
04 08 12 16 20 24 28 32 36
05 10 15 20 25 30 35 40 45
06 12 18 24 30 36 42 48 54
07 14 21 28 35 42 49 56 63
08 16 24 32 40 48 56 64 72
09 18 27 36 45 54 63 72 81
Upvotes: 2
Reputation: 140639
R (very similar to Matlab on this level): 12 characters.
> 1:9%*%t(1:9)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9]
[1,] 1 2 3 4 5 6 7 8 9
[2,] 2 4 6 8 10 12 14 16 18
[3,] 3 6 9 12 15 18 21 24 27
[4,] 4 8 12 16 20 24 28 32 36
[5,] 5 10 15 20 25 30 35 40 45
[6,] 6 12 18 24 30 36 42 48 54
[7,] 7 14 21 28 35 42 49 56 63
[8,] 8 16 24 32 40 48 56 64 72
[9,] 9 18 27 36 45 54 63 72 81
Upvotes: 2
Reputation: 304205
This resolves the complaint about the second parameter of main :)
main(x){for(x=8;x++<89;)printf("%.2d%c",x/9*(x%9+1),x%9<8?32:10);}
C - 77 chars
Based on dreamlax's 97 char answer. His current answer somewhat resembles this one now :)
Compiles ok with gcc, and main(x,y)
is fair game for golf i reckon
#define f(i){for(i=0;i++<9;)
main(x,y)f(x)f(y)printf("%.2d ",x*y);puts("");}}
Upvotes: 1
Reputation: 118691
puts (a=1..9).map{|i|a.map{|j|"%2d"%(j*i)}*" "}
Output
1 2 3 4 5 6 7 8 9
2 4 6 8 10 12 14 16 18
3 6 9 12 15 18 21 24 27
4 8 12 16 20 24 28 32 36
5 10 15 20 25 30 35 40 45
6 12 18 24 30 36 42 48 54
7 14 21 28 35 42 49 56 63
8 16 24 32 40 48 56 64 72
9 18 27 36 45 54 63 72 81
(If we ignore spacing, it becomes 39: puts (a=1..9).map{|i|a.map{|j|j*i}*" "}
And anyway, I feel like there's a bit of room for improvement with the wordy map
stuff.)
Upvotes: 0
Reputation: 239960
(No hope of coming anywhere near J, but languages with matrix ops are in a class of their own here...)
for$n(1..9){printf"%3d"x9 .$/,map$n*$_,1..9}
Upvotes: 2
Reputation: 512
Another attempt using C#/Linq with GroupJoin:
Console.Write(
String.Join(
Environment.NewLine,
Enumerable.Range(1, 9)
.GroupJoin(Enumerable.Range(1, 9), y => 0, x => 0, (y, xx) => String.Join(" ", xx.Select(x => x * y)))
.ToArray()));
Upvotes: 0
Reputation: 10550
C#
This is only 2 lines. It uses lambdas not extension methods
var nums = new List<int>() { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
nums.ForEach(n => { nums.ForEach(n2 => Console.Write((n * n2).ToString("00 "))); Console.WriteLine(); });
and of course it could be done in one long unreadable line
new List<int>() { 1, 2, 3, 4, 5, 6, 7, 8, 9 }.ForEach(n => { new List<int>() { 1, 2, 3, 4, 5, 6, 7, 8, 9 }.ForEach(n2 => Console.Write((n * n2).ToString("00 "))); Console.WriteLine(); });
all of this is assuming you consider a labmda one line?
Upvotes: 7
Reputation: 95335
#define f(i){int i=0;while(i++<9)
main()f(x)f(y)printf("%.2d ",x*y);puts("");}}
Upvotes: 2