CODEWITHSUNDEEP
pythonpython-3.x
jparikh97
jparikh97

Reputation: 105

Continuously subtracting- Python 3.X

I have a tuple like:

mytuple = (10,10)
mylist = []
mylist.append(mytuple)

I would like to subtract 1 from each iteration of x in mytuple until there is only 0 so that mylist would look like

[(10,10),(9,10),(8,10),(7,10),etc.,(0,10)]

I was thinking about a for loop, but I couldn't really figure out how to get this output. Thanks.

Upvotes: 1

Views: 171

Answers (3)

Josh Smith
Josh Smith

Reputation: 89

Try something like:

mytuple = (10,10)
mylist = [(i,mytuple[1]) for i in range(mytuple[0],-1,-1)]

Upvotes: 1

shuttle87
shuttle87

Reputation: 15934

range lets you specify the step taken with your iteration, which lets you do something like this:

mytuple = (10,10)
mylist = []
for i in range(mytuple[0], -1, -1):
    mylist.append((i, mytuple[1]))
print(mylist)

See this in action here: http://ideone.com/wnM5zb

Upvotes: 0

taesu
taesu

Reputation: 4580

mytuple = (10,10)
mylist = []
mylist.append(mytuple)
# store mytuple's first value
val = mytuple[0] 

# while val is greater than 0
while (val > 0):
    # subtract 1 from val
    val -= 1
    # generate tuple and add to list
    mylist.append((val,10))
print(mylist)

Upvotes: 1

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