I'm trying to delete an element from an array

Question

I'm trying to delete an element from an array by accepting the array as well as the element to be deleted. But when I print the array, the element prev to the element to be deleted is being displayed. How can I correct this?

import java.io.BufferedReader;
import java.io.InputStreamReader;

public class delete {
    void main() throws Exception {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        System.out.println("Enter the number of numbers");
        int n = Integer.parseInt(br.readLine());
        int x[] = new int[n];
        System.out.println("Enter the numbers");
        for (int i = 0; i < n; i++) {
            x[i] = Integer.parseInt(br.readLine());
        }
        System.out.println("Enter the number you want to delete");
        int d = Integer.parseInt(br.readLine());
        boolean b;
        int i = 0;
        for (; i < n; i++) {
            if (x[i] == d) {
                b = true;
                break;
            }
        }
        int q = i;//index position of the element to be deleted

        int x2[] = new int[n - 1];
        for (int k = 0; k < n - 1; k++) {
            if (q != k)
                x2[k] = x[k];
            if (q == k)
                x2[k] = x[k + 1];
        }

        for (int j = 0; j < n - 1; j++) {
            System.out.println(x2[j]);
        }
    }
}

Answer 1

The problematic snippet in OPs code is:

for (int k = 0; k < n - 1; k++) {
    if (q != k)
        x2[k] = x[k];
    if (q == k)
        x2[k] = x[k + 1];
}

As said in my first comment, this is not able to correctly write each value behind q into the new array.

Let's assume the following variables:

int n = 9;
int q = 5;
int[] x = {1, 2, 3, 4, 5, 6, 7, 8, 9};
int[] x2 = new int[n - 1];

After running the mentioned loop, x2 will then be [1, 2, 3, 4, 5, 7, 7, 8], because in if (q == k) OP writes the value of the following index, if it reaches the ignored index and on the next iteration it writes the excact same index again with if (q != k) x2[k] = x[k];. That is why "7" occurs twice.

An easy way to fix this is using two separates loops, like OP has done after my suggestion:

for (int k = 0; k < q; k++) {
    x2[k] = x[k];
}
for (int k = q; k < n - 1; k++) {
    x2[k] = x[k+1];
}

The first loop writes each value before the ignored index and the second loop writes each value behind the ignored index.