CODEWITHSUNDEEP
pythonpython-2.7
Long Smith
Long Smith

Reputation: 1411

Compare bytes in Python

I get data over TCP and try to compare it with a known value (0xAD):

b, addr = sock.recvfrom(1)
h = "".join(hex(ord(i)) for i in b)
print h
if h == str(0xad):
    print "Work"
    data = bytearray()
    data.append(observer.OBSERVER_VALIDATION_BYTE)
    sock.sendto(data, 0, addr)

I tried to compare them like strings as it shown above and tried to compare them like bytes in two ways:

b[0] == 0xAD

or

b2 = bytearray()
b2.append(0xAD)
b2[0] == b[0]

And all of the comparisons failed, though. print h gives me 0xad.

I have a set of bytes defined like BYTE = 0xAD. I need to send them over TCP and compare the read result.

If I define them like strings (BYTE = '0xAD'), it provides an ability to compare, but I can't put them in the bytearray to send because bytearr.append(BYTE) reasonably returns an error. So I can't redefine them as strings. So what is the way to compare bytes got from sock.recvfrom and value declared in the way I have?

Upvotes: 6

Views: 31645

Answers (1)

eugecm
eugecm

Reputation: 1249

If your problem is casting, you can cast variable BYTES to a bytearray this way:

>>> BYTE = '0xAD'
>>> ba = bytearray([int(BYTE, 16)])

Then compare bytearrays using ==.

Upvotes: 2

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