CODEWITHSUNDEEP
carrayspointers2d
digeridoo
digeridoo

Reputation: 153

return from incompatible pointer type?

I get the warning Return from incompatible pointer type in line where I return sarray, why though? I have been trying to figure out for a while now.. I also get a warning for incompatible pointer type in line

( *iarray )[CHARACTER_LIMIT] = scanCode();

but I think if I fixed the first part, this would be easier to fix this one.

#include <stdio.h>
#define MAX_WORDS 9054 //Scope variables
#define CHARACTER_LIMIT 6
#define MAX_TRIPLETS 3018


char** scanCode(void)  
{
    FILE *in_file;
    int i = 0;
    static char sarray[MAX_WORDS][CHARACTER_LIMIT];
    in_file = fopen("message.txt", "r");
    for(i=0; i<WORD_COUNT_MAX; i++)    {
        fscanf(in_file,"%s", sarray[i]);
    }

    return sarray;
    fclose(in_file);
}

int main(void)
{

    char ( *iarray )[CHARACTER_LIMIT] = scanCode();  

    while(1);
    return 0;
}

Upvotes: 0

Views: 1939

Answers (1)

juanchopanza
juanchopanza

Reputation: 227370

sarray is an array or arrays, which can decay to pointer to array, but not pointer to pointer. Converting sarray to char** should be an error.

Besides that, scanCode() returns a pointer to pointer to char. iarray is a pointer to array of char with length CHARACTER_LIMIT. These are not the same type, and the compiler is warning you about this.

You need to change either the return type of the function:

char (*scanCode(void))[CHARACTER_LIMIT] {
  ....
  return sarray;
}

Here, sarray decays to a pointer to array of length CHARACTER_LIMIT.

Upvotes: 2

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