Reputation: 944
I have a Api Post method that I want to be able to accept any file type and that looks like this:
[HttpPost]
public async Task<IHttpActionResult> Post()
{
if (!Request.Content.IsMimeMultipartContent())
{
throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
}
var provider = new MultipartMemoryStreamProvider();
await Request.Content.ReadAsMultipartAsync(provider);
if (provider.Contents.Count != 1)
{
throw new HttpResponseException(Request.CreateResponse(HttpStatusCode.BadRequest,
"You must include exactly one file per request."));
}
var file = provider.Contents[0];
var filename = file.Headers.ContentDisposition.FileName.Trim('\"');
var buffer = await file.ReadAsByteArrayAsync();
}
This works in fiddler when I try to post an image to it. However, I'm writing a client library and I have a method that looks like this:
public string PostAttachment(byte[] data, Uri endpoint, string contentType)
{
var request = (HttpWebRequest)WebRequest.Create(endpoint);
request.Method = "POST";
request.ContentType = contentType;
request.ContentLength = data.Length;
var stream = request.GetRequestStream();
stream.Write(data, 0, data.Length);
stream.Close();
var response = (HttpWebResponse) request.GetResponse();
using (var reader = new StreamReader(response.GetResponseStream()))
{
return reader.ReadToEnd();
}
}
Whenever I try to post an image using this, I'm getting a UnsuportedMediaType error. I'm assuming it's because my image isn't Multi Part Content? Is there an easy way to make my request of the correct type?
If I have to change my web api post method, is there an easy way of doing that without writing files to the server and keeping it in memory?
Upvotes: 4
Views: 22898
Reputation: 1917
The MultipartFormDataContent
from the System.Net.Http
namespace will allow you to post multipart form data.
private async Task<string> PostAttachment(byte[] data, Uri url, string contentType)
{
HttpContent content = new ByteArrayContent(data);
content.Headers.ContentType = new MediaTypeHeaderValue(contentType);
using (var form = new MultipartFormDataContent())
{
form.Add(content);
using(var client = new HttpClient())
{
var response = await client.PostAsync(url, form);
return await response.Content.ReadAsStringAsync();
}
}
}
Upvotes: 5