Reputation: 40653
I have a table similar to this:
=================
| Id | ParentId |
=================
| 1 | 0 |
-----+-----------
| 2 | 1 |
-----+-----------
| 3 | 0 |
-----+-----------
| 4 | 3 |
-----+-----------
| 5 | 3 |
-----+-----------
| 6 | 0 |
-----+-----------
| 7 | 6 |
-----+-----------
| 8 | 7 |
-----------------
Given an Id, I need to know its root "node" Id. So,
There is no limit to the levels of the hierarchy. Is there a SQL that can do what I need?
Upvotes: 5
Views: 5421
Reputation: 12218
I used @Kris answer for a while successfully, until I faced an issue where a child node might got deleted (accidentally), as a result the function gets into an infinite loop and hangs the mysql database at all, following is the modified version which works in my case:
DELIMITER $$
CREATE FUNCTION `FindRootNode`(InputValue INT(11)) RETURNS INT(11)
NO SQL
BEGIN
DECLARE ReturnValue, _ParentId INT;
SELECT InputValue INTO _ParentId;
REPEAT
SET ReturnValue = _ParentId;
SELECT IFNULL((SELECT parent_id FROM TableName WHERE id=ReturnValue), 0) INTO _ParentId;
UNTIL _ParentId = 0
END REPEAT;
RETURN ReturnValue;
END $$
DELIMITER ;
Usage1
SELECT CompanyCategoryTestRoot(HERE_COMES_CHILD_NODE_VALUE)
Upvotes: 0
Reputation: 2760
Here is a short query doing what you're asking, assuming your table is called foo
and that you want to know the root of <id>
:
SELECT f.Id
FROM (
SELECT @id AS _id, (SELECT @id := ParentId FROM foo WHERE Id = _id)
FROM (SELECT @id := <id>) tmp1
JOIN foo ON @id <> 0
) tmp2
JOIN foo f ON tmp2._id = f.Id
WHERE f.ParentId = 0
Upvotes: 3
Reputation: 41867
Actually, you can quite easily do this using a function.
Try running the following .sql script on your favorite empty test database.
--
-- Create the `Nodes` table
--
CREATE TABLE `Nodes` (
`Id` INT NOT NULL PRIMARY KEY
,`ParentId` INT NOT NULL
) ENGINE=InnoDB;
--
-- Put your test data into it.
--
INSERT INTO `Nodes` (`Id`, `ParentId`)
VALUES
(1, 0)
, (2, 1)
, (3, 0)
, (4, 3)
, (5, 3)
, (6, 0)
, (7, 6)
, (8, 7);
--
-- Enable use of ;
--
DELIMITER $$
--
-- Create the function
--
CREATE FUNCTION `fnRootNode`
(
pNodeId INT
)
RETURNS INT
BEGIN
DECLARE _Id, _ParentId INT;
SELECT pNodeId INTO _ParentId;
my_loop: LOOP
SELECT
`Id`
,`ParentId`
INTO
_Id
,_ParentId
FROM `Nodes`
WHERE `Id` = _ParentId;
IF _ParentId = 0 THEN
LEAVE my_loop;
END IF;
END LOOP my_loop;
RETURN _Id;
END;
$$
--
-- Re-enable direct querying
--
DELIMITER ;
--
-- Query the table using the function to see data.
--
SELECT
fnRootNode(`Nodes`.`Id`) `Root`
,`Nodes`.`Id`
,`Nodes`.`ParentId`
FROM `Nodes`
ORDER BY
fnRootNode(`Nodes`.`Id`) ASC
;
-- EOF
Output will be:
Root Id ParentId
==== ==== ========
1 1 0
1 2 1
3 3 0
3 4 3
3 5 3
6 6 0
6 7 6
6 8 7
Upvotes: 10
Reputation: 70540
In short: no. Look at regular Bill Karwin's excellent presentation about hierarchical models and it's uses, shortcomings, and how to get around those: http://www.slideshare.net/billkarwin/models-for-hierarchical-data
Upvotes: 0
Reputation: 839074
This is quite difficult to do in MySQL because it doesn't yet support recursive common table expressions.
I'd suggest instead using a nested sets model, or else storing the root node in the row and updating it as the structure changes.
Upvotes: 0