Reputation: 33
I am learning Spring MVC and when I am trying to run the html file it gives the error HTTP Status 500 - Servlet.init()
for servlet spring-dispatcher threw exception
This is my web.xml
<?xml version="1.0" encoding="UTF-8"?>`<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>FirstSpringMVC</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
This is my spring-dispatcher-servlet
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
<bean id="HandlerMapping" class = "org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping"/>
<bean name = "/welcome.html" class = "com.ankitud.hellocontroller.HelloController"/>
<bean id = "viewResolver"
class = "org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name = "prefix">
<value>/WEB-INF/</value>
</property>
<property name = "suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
This is my jsp page
<html>
<head>
<title>First MVC Application</title>
</head>
<body>
<h1>First MVC Application</h1>
<h2>${welcomemessage}</h2>
</body>
</html>
This is my HelloController class
package com.ankitud.hellocontroller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.AbstractController;
public class HelloController extends AbstractController {
@Override
protected ModelAndView handleRequestInternal(HttpServletRequest request, HttpServletResponse response) throws Exception{
ModelAndView modelandview = new ModelAndView("HelloPage");
modelandview.addObject("welcomemessage", "Hi User, welcome to the first Spring MVC application");
return modelandview;
}
}
And this is the exception that I am getting
javax.servlet.ServletException: Servlet.init() for servlet spring-dispatcher threw exception
org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:502)
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:79)
org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:616)
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:521)
org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1096)
org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:674)
org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1500)
org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.run(NioEndpoint.java:1456)
java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
java.lang.Thread.run(Thread.java:745)
I am working with Eclipse 4.5.1 , Tomcat 8.0.30 and Spring 4.2.3.
Upvotes: 3
Views: 63646
Reputation: 1
This might be too late but I he's the solution for any help seeker in future. There are 2 blocks which are missing in the code:
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
@Controller
public class HelloController extends AbstractController {
//Your class content goes here
}
This will solve your routing issues and now you can visit /welcome.html. Though you would still see ${welcomemessage} as it is when you route to /welcome.html. Finally in order to see the actual object data on the jsp page, simply add
<%@ page contentType="text/html; charset=UTF-8" isELIgnored="false" %>
That's it! This would help you access your welcomemessage object in your Jsp page. Hope this helps :)
Upvotes: 0
Reputation: 1
In the spring-dispatcher-servlet.xml instead of the below code
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
try using this code
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
I tried and it worked for me. Happy coding.
Upvotes: 0
Reputation: 8387
You missed this block from your web.xml try to add it:
<web-app...>
<!-------- DispatcherServlet definition goes here----->
....
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
</web-app>
Upvotes: 3