CODEWITHSUNDEEP
citerationscanfstdin
Quinn Tai
Quinn Tai

Reputation: 55

Iterating through a string from stdin in C

I want to read in the first 20 characters from stdin. Would I be able to just use a for loop that iterates 20 times and scanf("%c",&var)? What would happen if the input is less than 20 characters long?

I was thinking of using gets() to bypass this issue. Read in the entire line, then iterate over the string either until a counter reaches 20 or the end of string is reached. However, is there a way I can detect the end of a string?

Or is there a better way?

Only asking this because we're not allowed to use any of the functions from the string.h library.

Upvotes: 2

Views: 1787

Answers (4)

August Karlstrom
August Karlstrom

Reputation: 11377

Here is a solution using basic fgetc:

#include <stdio.h>

#define LEN(arr) ((int) (sizeof (arr) / sizeof (arr)[0]))

static void ReadLine(FILE *file, char result[], int resultLen)
{
    int i, ch;

    ch = fgetc(file);
    i = 0;
    while ((ch != EOF) && (ch != '\n') && (i < resultLen - 1)) {
        result[i] = ch;
        ch = fgetc(file);
        i++;
    }
    result[i] = '\0';
}


int main(void)
{
    char s[20 + 1];

    ReadLine(stdin, s, LEN(s));
    puts(s);
    return 0;
}

Upvotes: 1

Holt
Holt

Reputation: 37616

Here is a short version which works using scanf:

#include <stdio.h>

int main(void) {
    char buffer[20 + 1] ; // 20 characters + 1 for '\0'
    int  nread ;
    nread = scanf("%20[^\n]", buffer) ; // Read at most 20 characters
    printf("%s\n", buffer);
    return 0;
}

scanf will automatically add the '\0' character at the right place in buffer and with the "%20[^\n]" it will read at most 20 characters different from '\n'.

If you want to put this in a function and avoid repeating 20 (error prone):

#include <stdio.h>

int read_chars (char buffer[], int len) {
    char format[50] ;
    sprintf(format, "%%%d[^\n]", len);
    return scanf(format, buffer) ;
}

#define MAX_CHARS 20

int main(void) {
    char buffer[MAX_CHARS + 1] ; // 20 characters + 1 for '\0'
    read_chars (buffer, MAX_CHARS) ;
    printf("%s\n", buffer);
    return 0;
}

Edit: If you don't want to use sprintf to create the format string, you could use preprocessor (will not work if MAX_CHARS is not a preprocessor constant):

#include <stdio.h>

#define _READ_CHARS(buffer, N) scanf("%" #N "[^\n]", buffer)
#define READ_CHARS(buffer, N) _READ_CHARS(buffer, N)

#define MAX_CHARS 20

int main(void) {
    char buffer[MAX_CHARS + 1] ; // 20 characters + 1 for '\0'
    READ_CHARS (buffer, MAX_CHARS) ;
    printf("%s\n", buffer);
    return 0;
}

Upvotes: 0

sestus
sestus

Reputation: 1927

Just use read:

    #include <stdio.h>
    #include <stdlib.h>
    #include <errno.h>

    int main(){
        //Declare the reading buffer. Need 1 more position to add '\0'
        char buffer[21];

        int char_num;
        if ((char_num = read(0, buffer, 20)) < 0) {
            perror("read: ");
            exit(1);
        }
        //means that there were less than 20 chars in stdin
        //add the null character after the last char and return
        else if (char_num < 20) {
            //terminate the string after the last char read from stdin
            buffer[char_num] = '\0';
            close(0);
            printf("%s\n", buffer);
        }
        //means that there were more than 20 (or exactly 20 chars on stdin)
        else {
            buffer[20] = '\0';
            printf("%s\n", buffer);
            //now it depends on what you want to do with the remaining chars
            //this read just discard the rest of the data, in the same buffer
            //that we ve used. If you want to keep this buffer for some other
            //task, figure out some other solution
            while(1) {
                if ((char_num = read(0, buffer, 20)) < 0) {
                    perror("read: ");
                    exit(1);
                }
                close(0);
                if (char_num == 0 || char_num < 20)
                    break;
            }
        }
        return 0;
    }

Upvotes: 0

Nutan
Nutan

Reputation: 786

You can try this way...

1 - Read first 20 characters of a line by using scanf() as shown in example given below in a character array .

for example : 

  char str[21];

  scanf("%20[^\n]s",str);

2 - Finally you will have first 20 characters from line in your character array .

3 - if the line length is less than 20 then it will automatically assign the '\0' character at the end of line .

and if you want to find total number of characters in a array then calculate the length of the array

**The end of a string is determine by using the '\0' NULL character

Upvotes: 1

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