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mskuratowski
mskuratowski

Reputation: 4124

Deserialize json arrays with newtonsoft

how can I deserialize json arrays with newtonsoft?

Here my json file:

{
    "one": [
      {
        "one":"1",
        "two":"2", 
        "three":"3"
      },
      {
        "one":"1",
        "two":"2", 
        "three":"3"
      }
    ],
    "two": [
      {
        "one":"1",
        "two":"2", 
        "three":"3"
      }
    ]
}

Here is my code:

myList= JsonConvert.DeserializeObject <List<MyClass>>(jsonFile);

public class MyClass
{
    public string one{ get; set; }
    public string two { get; set; }
    public string three { get; set; }
}

Maybe I need change in some way my json file?

Upvotes: 0

Views: 163

Answers (5)

JOSEFtw
JOSEFtw

Reputation: 10091

You should deserialize it as a Dictionary<string, MyClass[]>

var test = "{ \"one\": [ { \"one\":\"1\", \"two\":\"2\", \"three\":\"3\" }, { \"one\":\"1\", \"two\":\"2\", \"three\":\"3\" } ], \"two\": [ { \"one\":\"1\", \"two\":\"2\", \"three\":\"3\" } ] }";
var testar = JsonConvert.DeserializeObject <Dictionary<string, MyClass[]>>(test);

This would work out of the box if there is more keys added like Forth, Fifth and so on.

enter image description here

Upvotes: 0

CodeCaster
CodeCaster

Reputation: 151730

That is no JSON array, it is an object with two array properties.

Use http://json2csharp.com:

public class YourClass
{
    public string one { get; set; }
    public string two { get; set; }
    public string three { get; set; }
}

public class RootObject
{
    public List<YourClass> one { get; set; }
    public List<YourClass> two { get; set; }
}

(Don't we still have a canonical question for this? Every day the same...)

Upvotes: 0

croxy
croxy

Reputation: 4178

If you want to keep your class structure you have to change your json file into this:

[
   {
      "one":"1",
      "two":"2",
      "three":"3"
   },
   {
      "one":"1",
      "two":"2",
      "three":"3"
   }
]

With this json file style the deserialization 

myList= JsonConvert.DeserializeObject <List<MyClass>>(jsonFile);

will complete properly.

Your above json file has two arrays in it. Because of that the deserialization will fail.

Upvotes: 0

Vaibhav Chaurasiya
Vaibhav Chaurasiya

Reputation: 166

Try This : 

`public class Foo
{
    [JsonProperty("one")]
    public string One { get; set; }
    [JsonProperty("two")]
    public string Two { get; set; }
    [JsonProperty("three")]
    public string Three { get; set; }
}
public class RootObject
{
    [JsonProperty("one")]
    public List<Foo> One { get; set; }
    [JsonProperty("two")]
    public List<Foo> Two { get; set; }
}`

and to deserialize object use 

` RootObject _rootObject = JsonConvert.DeserializeObject<RootObject>
  (jObject.ToString());`

Upvotes: 0

Yuval Itzchakov
Yuval Itzchakov

Reputation: 149646

Your class needs to match the structure your JSON. It should look like this:

public class Foo
{
    [JsonProperty("one")]
    public string One { get; set; }
    [JsonProperty("two")]
    public string Two { get; set; }
    [JsonProperty("three")]
    public string Three { get; set; }
}

public class RootObject
{
    [JsonProperty("one")]
    public List<Foo> One { get; set; }
    [JsonProperty("two")]
    public List<Foo> Two { get; set; }
}

Now it will properly deserialize:

Console.WriteLine(JsonConvert.DeserializeObject<RootObject>(json));

Upvotes: 1

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