CODEWITHSUNDEEP
pythonrename
AndrewC10
AndrewC10

Reputation: 357

Python Renaming Multiple Files in Directory

Beginner question: I am trying to rename all .xlsx files within a directory. I understand how to replace a character in string with another, but how about removing? More specifically, I have multiple files in a directory: 0123_TEST_01, 0456_TEST_02. etc. I am trying to remove the prefix in the file name, which would result in the following: TEST_01, TEST_02.

I am attempting to use os.rename and throw it into a loop, but am unsure if I should use len() and some math to try and return the correct naming convention. The below code is where I currently stand. Please let me know if this does not make sense. Thanks.

import os
import shutil
import glob

src_files = os.listdir('C:/Users/acars/Desktop/b')

for file_name in src_files: 
       os.rename(fileName, filename.replace())

Upvotes: 3

Views: 2351

Answers (2)

Padraic Cunningham
Padraic Cunningham

Reputation: 180502

Just split once on an underscore and use the second element, glob will also find all your xlsx file for you are return the full path:

from os import path, rename
from glob import glob

src_files = glob('C:/Users/acars/Desktop/b/*.xlsx')
pth = 'C:/Users/acars/Desktop/b/'

for file_name in src_files:         
    rename(file_name, path.join(pth, path.basename(file_name).split("_",1)[1])

If you only have xlsx files and you did not use glob you would need to join the paths:

from os import path, rename
from glob import glob


pth = 'C:/Users/acars/Desktop/b'
src_files = os.listdir(pth)

for file_name in src_files:
    new = file_name.split("_", 1)[1]
    file_name = path.join(pth, file_name)
    rename(file_name, path.join(pth, new))

Upvotes: 1

ComputerFellow
ComputerFellow

Reputation: 12108

Just split the file name by underscore, ignore the first part, and join it back again.

>>> file_name = '0123_TEST_01'

>>> '_'.join(file_name.split('_')[1:])
'TEST_01'

Your code will look like this: 

for file_name in src_files:
     os.rename(file_name, '_'.join(file_name.split('_')[1:]))

Upvotes: 1

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