CODEWITHSUNDEEP
androidjsonstringif-statement
H4F
H4F

Reputation: 131

check if json string =1 display one or 2 display two ect

My json array responce for item location as "id_location" : "1" or 2 ect i want to display the equal value " location name" in my site insted of the numbers. So how to check and change it beforre setText , changing it by using ready value from string.xml is a good idea but how to do it Thanks in advance

EDIT This is how i get json 

  List adlist = new List();

 ad.setTitle(obj.getString("id_location"));

With list adapter

-------EDIT 2------ If alians saw this in futer.. Thanks to mr.vaspalls This is the fainal working code :

//m.getLocation() is your json returned string
switch(m.getLocation()){
 case "1":  textview.setText("New York");
               break;
 case "2": textview.setText("London");
              break;
  .....
 }

Upvotes: 0

Views: 43

Answers (2)

Pankaj Nimgade
Pankaj Nimgade

Reputation: 4549

if you already know all the default values for the cities, you can either save them in the String.xml for save it in a class like this 

String[] location = {"","London","Berlin","Mascow"}

OR

 String[] location = getResources().getStringArray(R.array.location);

I made the first index empty as i don't know if you will be getting a location value for it.

but if you have a value for 0 like "some city", then location array should not be empty at index 0

int index = Integer.parseInt(jsonObject.getString("id_location"));
textView.setText(""+location[i]);

Upvotes: 1

Vasileios Pallas
Vasileios Pallas

Reputation: 4877

The easiest way is to do that with switch like this

switch(id_location){
     case "1":  city = "New York";
                   break;
     case "2": city = "London";
                    break;
      .....
 }

Upvotes: 1

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