CODEWITHSUNDEEP
c#linqdictionary
Girish Kumar
Girish Kumar

Reputation: 113

Reading the dictionary element values

I have the below code where I want to read the value of dictionary 'filter' using for loop.'filter[1]'again has two values. Since dictionary is key value pair, how do I access the element value below.

class program
{
public string RecSys { get; set; }
public string AnsSys { get; set; }
public string IsAddOn { get; set; }
public string Country { get; set; }

public static void Main()
{
    program p1 = new program();
    program p2 = new program();
    program p3 = new program();
    List<program> List = new List<program>();

    p1.RecSys = "RY1";
    p1.AnsSys = "CSCLRC";
    p1.IsAddOn = "P";
    p1.Country = "India";
    List.Add(p1);

    p2.RecSys = "RY1";
    p2.AnsSys = "APEX";
    p2.IsAddOn = "primary";
    p2.Country = "Pakistan";
    List.Add(p2);

    p3.RecSys = "RY1";
    p3.AnsSys = "APEX";
    p3.IsAddOn = "Addon";
    p3.Country = "Pakistan";
    List.Add(p3);

    var filter = List.GroupBy(item => new { item.RecSys, item.AnsSys }).ToDictionary(grp => grp.Key, grp => grp.ToList()).Values;

    for (int i = 0; i < filter.Count; i++)
    {
        // read the values. 'filter[1]'again has two values 
    }
}

}

Upvotes: 0

Views: 28

Answers (1)

Rahul Singh
Rahul Singh

Reputation: 21795

You can fetch the values using two foreach loop like this:-

foreach (var item in filter)
{
    foreach (var innerItem in item)
    {
         Console.WriteLine(innerItem.IsAddOn);
         Console.WriteLine(innerItem.Country);
         //and so on..
    }
}

Or else if you want all the Values of dictionary at once then you can flatten it using SelectMany:-

var filter = List.GroupBy(item => new { item.RecSys, item.AnsSys })
                 .ToDictionary(grp => grp.Key, grp => grp.ToList())
                 .SelectMany(x => x.Value);

and finally iterate over the items using a single foreach loop:-

foreach (var item in filter)
{
    Console.WriteLine(item.Country);
    Console.WriteLine(item.AnsSys);
    //and so on..
}

Upvotes: 2

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